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3 years ago

What is the simplified version of the expression below? 1/2(3/4x+10)-2(x+1)

Mathematics

1 answer:

Vladimir [108]3 years ago

7 0

Answer: -1 5/8 + 3 <em>or </em>-13/8 + 3

Step-by-step explanation:

1/2 (3/4x + 10) - 2 (x + 1)

3/8x + 5 - 2x - 2

Combine like terms

3/8x - 2x + 5 - 2

-1 5/8 + 3

-13/8 + 3

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4. The area of the parallelogram<br>is 81.9 in? What is the height

ipn [44]

Answer 96in2

Step-by-step explanation:

formula to find area = base x height

substitute the values

= 10 x 9

= 90 cm2

7 0

3 years ago

In a board game, Rose gets x + 4 points when she lands on a green space, 7x – 1 points for landing on a blue space, and -4x poin

ra1l [238]

Answer:

5x-3

Step-by-step explanation:

x+4+7x-1-4x

5x-3

3 0

3 years ago

Read 2 more answers

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Lesechka [4]

1. 6.73 x 10^6
2. 1.33 x 10^4
3.9.77 x 10^22
4. 3.84 x 10^5
The rest i didn’t understand what where you trying to say

7 0

3 years ago

Find the Z scores that separate the middle 27% of the distribution from the area in the tails of the standard normal distributio

vekshin1

Z- score is a statistical tool that is used to determine the probability of finding a number or a value under a normal distribution plot. A normal distribution assumes that the mean is equal to zero and that the standard deviation is equal to 1. Using the z-score table, we can find the probability either on the right side or the left side. Using the table hence, we find the probability to the left of the value. The probability that is equivalent to the unknown z should be equal to 0.5 + (0.27/2) = 0.635. 0.5 comes from the assumption that the area under the curve on each side is 50% of the total. The equivalent z score is equal to z = 0.345.

5 0

3 years ago

In a particular course, it was determined that only 70% of the students attend class on Fridays. From past data it was noted tha

siniylev [52]

Answer: Probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

Step-by-step explanation:

Since we have given that

Probability that students attend class on Fridays = 70% = 0.7

Probability that who went to class on Fridays would pass the course = 95% = 0.95

Probability that who did not go to class on Fridays would passed the course = 10% = 0.10

Let A be the event students passed the course.

Let E be the event that students attend the class on Fridays.

Let F be the event that students who did not attend the class on Fridays.

Here, P(E) = 0.70 and P(F) = 1-0.70 = 0.30

P(A|E) = 0.95, P(A|F) = 0.10

We need to find the probability that they did not attend on Fridays.

We would use "Bayes theorem":

$P(F\mid A)=\dfrac{P(F).P(A\mid F)}{P(E).P(A\mid E)+P(F).P(A\mid F)}\\\\P(F\mid A)=\dfrac{0.30\times 0.10}{0.70\times 0.95+0.30\times 0.10}\\\\P(F\mid A)=\dfrac{0.03}{0.695}=0.043$

Hence, probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

8 0

3 years ago