All categories

1 year ago

Rhonda can travel 45 miles in 3 hours while on her skateboard. at this rate, how many hours does it take to travel 1 mile

Mathematics

1 answer:

Rasek [7]1 year ago

6 0

The question is relating Rhonda's distance travelled and time taken

If 45 miles = 3 hours

Then, 1 mile = 3/45 hours

$=\frac{1}{15}$

Therefore, it will take Rhonda 1/15 hours to travel 1 mile.

You might be interested in

A rectangle is 3 feet longer than it is wide . if the perimeter is 30 feet , find the area in square feet .

noname [10]

Answer:

Hey

Step-by-step explanation:

I beleve you answer is 10 because 3 time 10 equals 30 and the question sais "3 times longer"

5 0

4 years ago

128/8 in distributive property

pav-90 [236]

Answer:

Step-by-step explanation:

7 0

4 years ago

Read 2 more answers

Please help me. i’ll give you brainliest points

monitta

Answer:

i dont know

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

In a three hour TV broadcast the commercials show 29% of the time. How many minutes of commercials are shown each hour? Round to

Sedaia [141]

Answer:

There are 17.4 minutes of commercials are shown each hour.

Step-by-step explanation:

An hour has 60 minutes.

So in 3 hours, there are 3*60 = 180 minutes.

The commercials show 29% of the time.

So we have 0.29*180 = 52.2 minutes, in total, of commercial.

Per hour, we have 52.2/3 = 17.4 minutes of commercial.

7 0

3 years ago

In the third week of July, a random sample of 40 farming regions gave a sample mean of x = $6.88 per 100 pounds of watermelon. A

suter [353]

Answer:

a. [6.6350,7.3950]

b. ME=0.5150

Step-by-step explanation:

a. Given that n=40, $\bar x=6.88$ and that: $z_{\alpha/2}=z_{0.05}=1.645$

The required 90% confidence interval can be calculated as:

$\bar x\pm(margin \ of \ error)\\\\\bar x\pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}\\\\6.88\pm(1.645\times \frac{1.98}{\sqrt{40}})\\\\=[6.3650,7.3950]$

Hence, the 90% confidence interval for the population mean cash value of this crop is [6.6350,7.3950]

b. The margin of error at 90% confidence interval is calculated as:

$ME= z_{\alpha/2}\frac{\sigma}{\sqrt{n}}\\\\=(1.645\times \frac{1.98}{\sqrt{40}})\\\\=0.5150$

Hence, the margin of error is 0.5150

8 0

4 years ago