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elena55 [62]
1 year ago
9

what is the force constant, in newtons per meter, needed to produce a period of 0.45 s for a 0.011-kg mass on the spring?

Physics
1 answer:
topjm [15]1 year ago
8 0

The force constant is 2.145 N/m.

<h3>What is spring constant?</h3>
  • The spring constant is the force required to stretch or compress a spring divided by the distance traveled by the spring. It is used to determine whether a spring is stable or unstable.
  • K is the proportionality constant, also known as the 'spring constant.' Hooke's law (F = -kx) specifies stiffness and strength via the k variable. The greater the value of k, the greater the force required to stretch an object to a given length.

Using the relation;

T = 2π√m/k

T = time period = 0.45 s

m =  mass of object in kilograms = 0.011kg

k = spring constant

To find k based on the formula,

k = 4 × (3.142)^2 × 0.011 / (0.45 )^2

k = 2.145 N/m

Therefore the force constant is 2.145 N/m.

To learn more about force refer to :

brainly.com/question/12785175

#SPJ4

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66kg | 2.2 pounds
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I set it up like this. The 66 kg crosses out with the 1kg. So you multiply the top 66 x 2.2 = 145.2 pounds
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The volume of a gas increases from 18.7 m3 to 25.1 m3 while the pressure changes from 1.82 atm to 1.41 atm. If the initial tempe
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The combined gas law says: (P₁*V₁)/T₁=(P₂*V₂)/T₂ where P is the pressure in Pascals, V is the volume in m³ and T is the temperature in degrees Kelvin. 

P₁=1.82 atm= 184411.5 Pa 
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Lets solve the combined gas equation for T₂:

T₂*(P₁*V₁)/T₁=(P₂*V₂), 

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T₂={(P₂*V₂)*T₁}/(P₁*V₁)=367.07 K=367 K

So the final temperature is T₂=367 K. 
5 0
3 years ago
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The terminal speed of a sky diver is 163 km/h in the spread-eagle position and 325 km/h in the nosedive position. Assuming that
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Answer:

\frac{A_1}{A_2}=3.97549776055

Explanation:

The equation for terminal velocity is v_t=\sqrt{\frac{2mg}{\rho AC_d}}, where m is the mass of the sky diver, g the gravitational acceleration, \rho the air density, A the effective cross-sectional area and C_d the drag coefficient.

It will be easier if we write this as v_t^2 A=\frac{2mg}{\rho C_d} and realize that for both situations the right hand side of that formula will be the same. This means that v_{t1}^2 A_1=v_{t2}^2 A_2=\frac{2mg}{\rho C_d}, so the ratio of the effective cross-sectional area A in the slower position (A_1 for v_{t1}=163 km/h) to that in the faster position (A_2 for v_{t2}=325 km/h) will be \frac{A_1}{A_2}=\frac{v_{t2}^2}{v_{t1}^2}=3.97549776055

4 0
4 years ago
Air conditioners are rated by their coefficient of performance at 61 ∘ F inside temperature and 99 ∘ F outside temperature. An e
vovikov84 [41]

Answer:

the maximum possible coefficient performance is 13.7

Explanation:

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according to Carnot's theorem, the coefficient of performance is

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thus,

COP_{max}  = \frac{289.26}{310.37-289.26}

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A wheel which is initially at rest starts to turn with a constant angular acceleration. after 4 seconds it has made 4 complete r
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