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Strike441 [17]
3 years ago
10

A rock held by a person above the floor, but not dropped, is an example of which of newton's laws? i. the velocity is constant i

n the absence of a net force. ii. the acceleration of an object is directly proportional to and in the same direction as the net force acting on the object. iii. when one object exerts a force on a second object, the second object exerts an equal force in the opposite direction on the first object.
Physics
1 answer:
ycow [4]3 years ago
7 0
It is not i
I think the answer is iii but I'm not sure
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For the special case of straight line motion in the x direction, the average velocity takes the form: If the beginning and ending velocities for this motion are known, and the acceleration is constant, the average velocity can also be expressed as For this special case, these expressions give the same result. Example for non-constant acceleration#1

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Which test was conducted on the skin found under the victim’s nails?
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5g of ammonium nitrate was dissolved in 60g of water in an insulated container. The temperature at the start of the reaction was
Minchanka [31]

Answer: The energy absorbed by the reaction from the water is 996 Joules.

Explanation:

Energy absorbed by the reaction or energy lost by the water to the reaction,Q.

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Change is temperature=\Delta T=19^oC-23^oC=-4^oC

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Negative sigh indicates that energy was given by the water to the reaction.

The energy absorbed by the reaction from the water is 996 Joules.

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A load of 45N attached to a spring that is hanging vertically stretches the spring 0.14m. What is the spring constant?
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6 0
3 years ago
A man pulled a 13.0 kg object 11.8 cm vertically with his teeth. (a) How much work (in J) was done on the object by the man in t
jonny [76]

Answer:

(a)The work done by the man is -15.03J.

(b)The force exerted on the object is 127.4N.

Explanation:

Mass of the object pulled by the man is -13kg

Object is lifted 11.8 cm vertical with his teeth it means (displacement = +11.8cm = +0.118m)

Acceleration due to gravity is 9.8 \mathrm{m} / \mathrm{s}^{2}

(a) <u>Calculating the work done</u>:

Work done = mgh

Where "m" is mass of an object, "g" is acceleration due to gravity and "h" is the displacement.

\text { Work }=-13 \times 9.8 \times(+0.118 \mathrm{m})

\text { Work }=-15.03 \mathrm{J}

The work done by the man is -15.03J.

(b) <u>Calculating the force</u>:

Probably the man and the object are close to the exterior of the earth. If the rigidity required to maintained the object of consistent velocity interior the gravitational field of the earth is \mathrm{g}=9.8 \mathrm{m} / \mathrm{s}^{2}

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The force exerted on the object is 127.4N.

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