❤this is what i found hope it explains
Answer:
A, C, D and E are the true statement about current flowing.
Answer:
adaptive optics.
Explanation:
Light wave can be defined as an electromagnetic wave that do not require a medium of propagation for it to travel through a vacuum of space where no particles exist.
A lens can be defined as a transparent optical instrument that refracts rays of light to produce a real image.
A telescope can be defined as an optical instrument or device which comprises of a curved mirror and lenses used for viewing distant objects i.e objects that are very far away such as stars and other planetary bodies.
The technique called adaptive optics uses a high-speed computer to monitor atmospheric distortion and adjust the optics of a telescope to partially compensate for the seeing.
Basically, adaptive optics is used by astronomers to correct the distortions caused by the turbulence of the atmospheric conditions of the Earth in real-time, so as to have an image that is as sharp as anyone taken in space.
Answer:
Anyone can sit in a corner office and delegate tasks, but there is more to effective leadership than that. Effective leaders have major impacts on not only the team members they manage, but also their company as a whole. Employees who work under great leaders tend to be happier, more productive and more connected to their organization – and this has a ripple effect that reaches your business's bottom line
Explanation:
:)
Answer:
The direct current that will produce the same amount of thermal energy is 1.83 A
Explanation:
Given;
maximum current, I₀ = 2.59 A
The average power dissipated in a resistor connected in an AC source is given as;
![P_{avg} = I_{rms} ^2R](https://tex.z-dn.net/?f=P_%7Bavg%7D%20%3D%20I_%7Brms%7D%20%5E2R)
Where;
![I_{rms} = \frac{I_o}{\sqrt{2} }](https://tex.z-dn.net/?f=I_%7Brms%7D%20%3D%20%5Cfrac%7BI_o%7D%7B%5Csqrt%7B2%7D%20%7D)
![P_{avg} = (\frac{I_o}{\sqrt{2} } )^2R\\\\P_{avg} = \frac{I_o^2R}{2} ----equation(1)](https://tex.z-dn.net/?f=P_%7Bavg%7D%20%3D%20%28%5Cfrac%7BI_o%7D%7B%5Csqrt%7B2%7D%20%7D%20%29%5E2R%5C%5C%5C%5CP_%7Bavg%7D%20%3D%20%5Cfrac%7BI_o%5E2R%7D%7B2%7D%20----equation%281%29)
The average power dissipated in a resistor connected in a DC source is given as;
![P_{avg} = I_d^2R --------equation(2)](https://tex.z-dn.net/?f=P_%7Bavg%7D%20%3D%20I_d%5E2R%20--------equation%282%29)
where;
is direct current
Solve equation (1) and (2) together;
![I_d^2R = \frac{I_o^2R}{2} \\\\I_d^2 = \frac{I_o^2}{2} \\\\I_d=\sqrt{\frac{I_o^2}{2} } \\\\I_d = \frac{I_o}{\sqrt{2}} \\\\I_d = \frac{2.59}{\sqrt{2} } \\\\I_d = 1.83 \ A](https://tex.z-dn.net/?f=I_d%5E2R%20%3D%20%5Cfrac%7BI_o%5E2R%7D%7B2%7D%20%5C%5C%5C%5CI_d%5E2%20%3D%20%5Cfrac%7BI_o%5E2%7D%7B2%7D%20%5C%5C%5C%5CI_d%3D%5Csqrt%7B%5Cfrac%7BI_o%5E2%7D%7B2%7D%20%7D%20%20%5C%5C%5C%5CI_d%20%3D%20%5Cfrac%7BI_o%7D%7B%5Csqrt%7B2%7D%7D%20%5C%5C%5C%5CI_d%20%3D%20%5Cfrac%7B2.59%7D%7B%5Csqrt%7B2%7D%20%7D%20%5C%5C%5C%5CI_d%20%3D%201.83%20%5C%20A)
Therefore, the direct current that will produce the same amount of thermal energy is 1.83 A