Ask question

Ask question

All categories

2 years ago

12

Electron grops could be considered which of the following

1 answer:

Maurinko [17]2 years ago

5 0

Answer:

Electron groups could be considered as Lone pair electrons and bonded pairs of electrons.

Answer: Option D & B

Explanation:

The two or more electrons can be bonded by single bond, double bond, covalent bond of electrons can simply be lone pair of electrons. Unshared pair of electrons are generally termed as lone pair of electrons in an atom which are generally present in the outermost shell of atoms. Hence electron groups can be determined by bonded pairs and lone pairs of electrons.

I got this from another brainly user

You might be interested in

A car traveling at 30 m/s runs out of gas while traveling up a 10 slope. how far up the hill what coast before starting to roll

kaheart [24]

Answer:

264.7 m

Explanation:

The net force felt by the car travelling along the slope is equal to the component of the weight parallel to the slope, so:

$F=-mg sin \theta$

where

m is the mass of the car

g = 9.8 m/s^2 is the acceleration of gravity

$\theta=10^{\circ}$

and the negative sign is due to the fact the force is opposite direction to the motion of the car

The acceleration of the car is therefore:

$a=\frac{F}{m}=-gsin \theta=-9.8 sin 10^{\circ}=-1.7 m/s^2$

Now we can find how far the car went up the hill by using the equation:

$v^2-u^2 = 2ad$

where

v = 0 is the final velocity of the car

u = 30 m/s is the initial velocity

g = -1.7 m/s^2 is the acceleration

d is the distance covered

Solving for d,

$d=\frac{v^2-u^2}{2a}=\frac{0-30^2}{2(-1.7)}=264.7 m$

3 0

4 years ago

An endangered species is a species that has died out and no individuals are left. True or false

valentinak56 [21]

Answer:

the answer is false... ....

8 0

3 years ago

Read 2 more answers

PLEASE HELP!!!!!!!!!!!

Alexxandr [17]

I am 100% sure its A.

5 0

3 years ago

Read 2 more answers

A car is moving at 5 m/s. 2 seconds later, it is traveling at 17 m/s. How far did the car go?

vekshin1

Answer:

gh

Explanation:

3 0

3 years ago

A copper wire 12 cm long and a mass of 16 g is in a magnetic field of 1.2 T oriented perpendicular to the wire. What current wou

Ugo [173]

Answer:

Current, I = 1.08 A

Explanation:

Given that,

Length of the copper wire, l = 12 cm = 0.12 m

Mass of the wire, m = 16 g = 0.016 kg

Magnetic field, B = 1.2 T

The magnetic field is oriented perpendicular to the wire. We need to find the current in the wire.

Magnetic force, F = BIL

Force of gravity, F' = mg

F' = F

$BIL=mg$

$I=\dfrac{mg}{BL}$

$I=\dfrac{0.016\times 9.8}{1.2\times 0.12}$

I = 1.08 A

So, the current through the wire is 1.08 A. Hence, this is the required solution.

8 0

4 years ago