Answer:
= .75 gallons or 3 quarts
Step-by-step explanation:
Known
Problem:
4 gallons 2 quarts - 3 gallons 3 quarts
⇒ 2 quarts: 0.5 gallons
⇒ 3 quarts: 0.75 gallons
Add on both sides
4 + 0.5 = 4.5 gallons
3 + 0.75 = 3.75 gallons
This leaves the equation at:
- 4.5 gallons - 3.75 gallons
This equals 3 quarts or 0.75 gallons.
Answer:
x = -24ySimplifying
15y + (x + 9y) = 0
Remove parenthesis around (x + 9y)
15y + x + 9y = 0
Reorder the terms:
x + 15y + 9y = 0
Combine like terms: 15y + 9y = 24y
x + 24y = 0
Solving
x + 24y = 0
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-24y' to each side of the equation.
x + 24y + -24y = 0 + -24y
Combine like terms: 24y + -24y = 0
x + 0 = 0 + -24y
x = 0 + -24y
Remove the zero:
x = -24y
Simplifying
x = -24y
Step-by-step explanation:
This equation is written in slope intercept form, y=mx+b, with m being the slope and b being the y-intercept.
The slope of the line is 1.5 and the y-intercept is -2. The answer is A.
I hope this helps ;)
Answer:
The least possible score Pia can earn on the fourth assignment and still be able to finish the week with an average score of 90 on all five assignments is 86
Step-by-step explanation:
The information given are;
Pia's scores in the first three assignments = 87, 85, and 92
The question asks to find upon finishing the week's five assignments the least possible score that Pia can earn on the fourth assignment and still be able to have an average score of 90 on all five assignments
Let the least score required to have an average score of 90 on all five assignments be X
If X is the least score to obtain an average of 90 for the five assignments, then fifth assignment score, will be maximum possible score obtainable to allow the attainment of the average score of 90 which is 100, which gives;
(87 + 85 + 92 + X + 100)/5 = 90
∴ 5 × 90 = 450 = 87 + 85 + 92 + X + 100 = 364 + X
X = 450 - 364 = 86
Therefore, the least possible score Pia can earn on the fourth assignment and still be able to finish the week with an average score of 90 on all five assignments = 86.
