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1 year ago

7

Part 1: About how tall is the actual Willis Tower? About how tall is the actual Great Pyramid? Be prepared to explain your reaso

ning.

1 answer:

lesantik [10]1 year ago

3 0

100 m and 300 m based off the graph the Willis is 3x the size of the great Pyramid

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What's 12748 rounded to the nearest thousand

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12748 rounded to the nearest thousand is 13000

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Help me please i need help read carefully and answer right plz and show proof or evidence

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3 years ago

write three ratios that are equivalent to the one given:the ratio of right of right-handed students to left-handed students is 1

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3 years ago

Read 2 more answers

A plane is approaching an aircraft carrier at 25° angle of elevation from 3.2 miles away how far above sea level is the plane

s2008m [1.1K]

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$Height\approx 1.35\ miles$

Step-by-step explanation:

The angle of elevation $=25\textdegree$

It is $3.2\ miles$ away from the point.

If we imagine a right triangle having an angle $25\textdegree$ .

Hypotenuse $=3.2$ , Opposite=Height from sea level $(h)$

$\sin 25=\frac{opposite}{hypotenuse}\\\\\sin 25=\frac{h}{3.2}\\\\h=3.2\times \sin 25\\\\h=3.2\times 0.4226\\\\h=1.3524\approx 1.35\ miles$

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3 years ago

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Thickness measurements of ancient prehistoric Native American pot shards discovered in a Hopi village are approximately normally

rusak2 [61]

Answer:

(a) The probability that the thickness is less than 3.0 mm is 0.119.

(b) The probability that the thickness is more than 7.0 mm is 0.119.

(c) The probability that the thickness is between 3.0 mm and 7.0 mm is 0.762.

Step-by-step explanation:

We are given that thickness measurements of ancient prehistoric Native American pot shards discovered in a Hopi village are approximately normally distributed, with a mean of 5.0 millimeters (mm) and a standard deviation of 1.7 mm.

Let X = <u><em>thickness measurements of ancient prehistoric Native American pot shards discovered in a Hopi village.</em></u>

So, X ~ Normal( $\mu=5.0,\sigma^{2} =1.7^{2}$ )

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean thickness = 5.0 mm

$\sigma$ = standard deviation = 1.7 mm

(a) The probability that the thickness is less than 3.0 mm is given by = P(X < 3.0 mm)

P(X < 3.0 mm) = P( $\frac{X-\mu}{\sigma}$ < $\frac{3.0-5.0}{1.7}$ ) = P(Z < -1.18) = 1 - P(Z $\leq$ 1.18)

= 1 - 0.8810 = <u>0.119</u>

The above probability is calculated by looking at the value of x = 1.18 in the z table which has an area of 0.881.

(b) The probability that the thickness is more than 7.0 mm is given by = P(X > 7.0 mm)

P(X > 7.0 mm) = P( $\frac{X-\mu}{\sigma}$ > $\frac{7.0-5.0}{1.7}$ ) = P(Z > 1.18) = 1 - P(Z $\leq$ 1.18)

= 1 - 0.8810 = <u>0.119</u>

The above probability is calculated by looking at the value of x = 1.18 in the z table which has an area of 0.881.

(c) The probability that the thickness is between 3.0 mm and 7.0 mm is given by = P(3.0 mm < X < 7.0 mm) = P(X < 7.0 mm) - P(X $\leq$ 3.0 mm)

P(X < 7.0 mm) = P( $\frac{X-\mu}{\sigma}$ < $\frac{7.0-5.0}{1.7}$ ) = P(Z < 1.18) = 0.881

P(X $\leq$ 3.0 mm) = P( $\frac{X-\mu}{\sigma}$ $\leq$ $\frac{3.0-5.0}{1.7}$ ) = P(Z $\leq$ -1.18) = 1 - P(Z < 1.18)

= 1 - 0.8810 = 0.119

The above probability is calculated by looking at the value of x = 1.18 in the z table which has an area of 0.881.

Therefore, P(3.0 mm < X < 7.0 mm) = 0.881 - 0.119 = 0.762.

4 0

3 years ago