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Ber [7]
2 years ago
15

Simplify ((c∧6)÷(c-d))-3

Mathematics
1 answer:
Vlad [161]2 years ago
8 0

9514 1404 393

Answer:

  (c^3-3c^2d+3cd^2-d^3)/c^18

Step-by-step explanation:

It appears you want to simplify ...

  \left(\dfrac{c^6}{c-d}\right)^{-3}=\left(\dfrac{c-d}{c^6}\right)^3=\boxed{\dfrac{c^3-3c^2d+3cd^2-d^3}{c^{18}}}

__

The relevant rule for exponents is ...

  a^-b = 1/a^b

The coefficients of the expansion of the binomial are found in Pascal's triangle.

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Hello!

This question is about which values you are changing when you are transforming an equation.

Let's go through the parent function for an absolute value equation and its various transformations.

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Since we are only looking at horizontal and vertical transformations, we only need to worry about the c and d values.

The c value of a function determines a function's horizontal position, and the d value of a function determines a function's vertical position.

One thing to note here is that the c value is being subtracted from the x value, meaning that if the function is being transformed to the right, you would actually be subtracting that value, while the d value behaves like a normal value, if it is being added, the function is transformed up, and vice versa.

Now that we know this, let's write each expression.

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Hope this helps!

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