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insens350 [35]
3 years ago
7

An oil company is considering 2 sites on which to drill, described as follows:

Mathematics
1 answer:
Olegator [25]3 years ago
7 0
A)site A has a larger probablility of finding oil
B) the difference between amount of profitmade is 30 million.

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To prepare a chocolate cake, 2 1/4 cups of flour were used. How many grams of flour was used if each cup of flour weighs 120 gra
Marianna [84]
120/4 = 30
120 x 2 = 240
240 + 30 = 270
270 grams of flour were used
4 0
3 years ago
I guess u have to find the area
Nesterboy [21]
18
Because 6•3= 18
Hope this helped
7 0
4 years ago
Read 2 more answers
Is 5/3 a irrational number
Nataly [62]

Answer: No

Step-by-step explanation: To determine whether 5/3 is rational or irrational, it's important to understand that all fractions positive or negative are rational numbers.

So 5/3 is not an irrational number, it's rational.

4 0
4 years ago
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Peanuts are sold in 8-ounce and 12-ounce packages.
allsm [11]

Answer:

C) 24

Step-by-step explanation:

8; 16 24 32 40 48

12; 24 36 48 69 72

They both have the common multiple of 24 and 48 in the intermediate multiplication since 24 is half of 48 and is the smallest multiple that is the answer.

6 0
2 years ago
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Calculate the number of kilograms of mercury required to fill a pool that is 20.0 m x 50.0 m x 10.0 m. The density of mercury is
malfutka [58]

Answer:

m=135000000 Kg

Step-by-step explanation:

To find the number of kilograms of mercury we need to find how to relate density, mass and, volume. For this we shall recall the density formula:

\rho=\frac{m}{V}

where \rho is the density, m is the mass and, V is the volume.

We have the density and want to compute the mass so now we want to know the volume of the pool.

The volume of a rectangular pool is given by the fomula:

V= (length)(heigh)(width).

So for our pool

V= (20)(50)(10).

V= 10000m^{3}.

Our density is in g/mL, so the last thing we need to do before computing the mass is to express the density in Kg/m^{3} (this is because we want our mass in Kg and, we have our volume in m^{3}).

For the density conversion we have to remember that

1000mL = 1L

1L=0.001m^{3}

1000g=1Kg

so

\rho=13.5\frac{g}{mL}*\frac{1000mL}{1L}*\frac{1L}{0.001m^{3}}*\frac{1Kg}{1000g}   =13500\frac{Kg}{m^{3}}.

With this we can finally compute mass:

\rho=\frac{m}{V}

m=\rho*V

m=(13500*10000) Kg

m=135000000 Kg.

4 0
3 years ago
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