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nexus9112 [7]
1 year ago
5

I’m stuck on this question. any help would be greatly appreciated

Mathematics
1 answer:
Mademuasel [1]1 year ago
4 0

Using the Pythagorean theorem we get:

y^2+8^2=12^2.

Simplifying the above result we get:

y^2+64=144.

Subtracting 64 from the above equation we get:

\begin{gathered} y^2+64-64=144-64, \\ y^2=80. \end{gathered}

Therefore:

y=\sqrt{80}\approx8.9.

Answer:

y=8.9.

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kolbaska11 [484]

Answer:

\boxed{ \tt\longrightarrow \: Area \:  Of  \: Shaded \:  region  \: =\boxed{ \tt 39  \: in²}}

Step-by-step explanation:

<u>Given:</u>

The Dimensions of Parallelogram are 12 in.(Base) and 7 in.(Height)

<em>And,</em>

The Dimensions of Rectangle are 9 in.(Length) and 5 in.(Breadth).

<u>To Find</u>:

The Area of Shaded region

<u>Solution:</u>

When the dimensions of parallelogram and the dimensions of rectangle are given, we need to find the Shaded region using this formula:

\boxed{\tt \longrightarrow Area  = (Parallelogram  - Rectangle)}

We know that the formula of Parallelogram is base*height[b×h] and the formula of rectangle is length*breadth[l*b] .

\tt\longrightarrow \: Area =B×h-l×b

Put their values accordingly:

\longrightarrow  \tt Area = (12 \times 7 - 9 \times 5)in {}^{2}

<u>Simplify it.</u>

<em>[</em><em>Follow BODMAS Rule strictly while </em><em>simplifying]</em>

\tt\longrightarrow \: Area = (84 - 45 ) in {}^{2}

\tt\longrightarrow \: Area = 39 \:  {in}^{2}

Hence, the Area of Shaded region would be 39 in² or 39 sq. in. .

\rule{225pt}{2pt}

I hope this helps!

8 0
2 years ago
Read 2 more answers
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