<h3>Given</h3>
tan(x)²·sin(x) = tan(x)²
<h3>Find</h3>
x on the interval [0, 2π)
<h3>Solution</h3>
Subtract the right side and factor. Then make use of the zero-product rule.
... tan(x)²·sin(x) -tan(x)² = 0
... tan(x)²·(sin(x) -1) = 0
This is an indeterminate form at x = π/2 and undefined at x = 3π/2. We can resolve the indeterminate form by using an identity for tan(x)²:
... tan(x)² = sin(x)²/cos(x)² = sin(x)²/(1 -sin(x)²)
Then our equation becomes
... sin(x)²·(sin(x) -1)/((1 -sin(x))(1 +sin(x))) = 0
... -sin(x)²/(1 +sin(x)) = 0
Now, we know the only solutions are found where sin(x) = 0, at ...
... x ∈ {0, π}
Answer:
The original price of the tent = $320
Step-by-step explanation:
Let the original price be =$ 
Discount offered =
% of the orignal price = 
Original price is $80 more than sale price
Discount = Original price - Sale price = $80
So, we have

We need to solve for
to find original price
Dividing both sides by 

∴ The original price of the tent = $320
B. Yes, (1,4) is a solution
Answer:
8
Step-by-step explanation:
1 + 2(2*2) - 1
1 + 2(4) - 1
1 + 8 -1=8