Answer:
see below
Step-by-step explanation:
Dosage= 500 mg
Frequency= twice a day (every 12 hours)
Duration= 10 days
Number of dosage= 10*2= 20
residual drug amount after each dosage= 4.5%
We can build an equation to calculate residual drug amount:
d= 500*(4.5/100)*t= 22.5t, where d- is residual drug, t is number of dosage
After first dose residual drug amount is:
After second dose:
As per the equation, the higher the t, the greater the residual drug amount in the body.
Maximum residual drug will be in the body:
- d= 20*22.5= 450 mg at the end of 10 days
Maximum drug will be in the body right after the last dose, when the amount will be:
Answer: a
Step-by-step explanation:
All of those statements are true about imaginary numbers
The answer is
date
1 2 3 4 5 31
r1 r2 r3 r4 r5 . . . r31
1gm 2gms 3<span>gms 4gms 5gms . . . 31gms
r1+r2+ .... +r31= 31(31+1) /2=496gms (31 rings)
he only made 5 rings
31 rings----------> 496 gms
5 rings ------------> ? = 5 x496 / 31=80 gms
</span><span> the weights of those 5 rings was 80 gms</span>
The answer to this is 2000...
hope this helps and HAGD!
