Using the form y=a(x-h)²+k
We can look at the vertex (-3,-2) which gives us the values of h,k
h=3, k=-2
Thus y=a(x+3)²-2
Then we can solve for a using any point on the line
- I'll use (-4,-1)
Insert the values of x,y into y=a(x+3)²-2
--> x=-4, y=-1
y=a(x+3)²-2
-1=a(-4+3)²-2
-1=a(-1)²-2
a-2=-1
a=-1+2
a=1
Insert the value of a
y=1(x+3)²-2
= (x+3)²-2
Thus y=(x+3)²-2 is the final equation in standard form
Answer:
- Timmy has successfully shown Suzie's conjecture is incorrect
- Suzie's conjecture is correct if the smallest square in the sum is 1
Step-by-step explanation:
The sum of odd numbers 1 .. n is ((n+1)/2)², a perfect square. Suzie is right about that. What Timmy has shown is that she is incorrect that the conjecture applies to <em>any</em> sum of consecutive odd numbers.
Timmy's sum of 5+7+9 is incorrect; it is 3·7 = 21. But, Timmy has the right idea. The sum of an arbitrary set of consecutive odd numbers will be the difference of two squares, but not necessarily a perfect square.
Good evening ,
_______
Answer:
<h2>b)</h2><h2>i) 50 km/h</h2><h2>ii) 75 km/h</h2><h2>iii) 50 km/h</h2>
_____________________
Step-by-step explanation:
b)
i) (50-0)÷(10-9)
=50
ii) (150-75)÷(12-11)
=75
iii) (150-0)÷(12-9)
=50.
_____________________
:)
The software rendering this question really butchered it... I think it's saying the displacement vector for the particle is
Differentiate twice with respect to time 
to get the velocity and acceleration vectors, respectively:
Then at 
, the acceleration of the particle is
which most closely resembles the first choice.
