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12345 [234]
1 year ago
9

There is a distance of 2m between the centers of two identical spheres, each with a mass of 25 kg. What is the magnitude and the

gravitational force that one sphere exerts on the other?

Physics
1 answer:
Degger [83]1 year ago
7 0

Given:

The mass of each sphere is

m_1=m_2\text{= 25 }kg

The distance between the two spheres is r = 2 m

To find the gravitational force that one sphere exerts on the other.

Explanation:

The gravitational force is caculated by the formula

F=G\frac{m_1m_2}{r^2}

Here, the universal gravitational constant is

G=\text{ 6.67}\times10^{-11}Nm^2kg^{-2}

Substituting the values, the gravitational force will be

\begin{gathered} F=\frac{6.67\times10^{-11}\times25\times25}{(2)^2} \\ =\text{ 1.04}\times10^{-8}\text{ N} \end{gathered}

Final Answer: The gravitational force that one sphere exerts on the other is 1.04 x10^-8 N.

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Marianna [84]

Answer:183.94 N

Explanation:

Given

Time Period T=5.3 s

mass of child m=48.5 kg

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Velocity v=\frac{2\pi \cdot r}{T}

v=\frac{2\pi \cdot 2.7}{5.3}

v=3.20 m/s

Now Centripetal Force will be Balanced by Frictional Force

Centripetal Force F_c=m\cdot \frac{v^2}{r}

F_c=48.5\cdot \frac{3.2^2}{2.7}

F_c=183.94 N

therefore Friction Force is 183.94 N

4 0
3 years ago
Which of the following is a scalar quantity?
raketka [301]

A scalar quantity is one in which there is no direction given.


30 Lbs would be the answer, since there is no indicator of direction.

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3 years ago
Astone is thrown directly upward with an initial speed of 9.6 m/s from a height of 12.8 m. After what time interval (in s) does
lara31 [8.8K]

Answer:

1.89 seconds

Explanation:

t = Time taken

u = Initial velocity = 9.6 m/s

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

v=u+at\\\Rightarrow 0=9.6-9.8\times t\\\Rightarrow \frac{-9.6}{-9.8}=t\\\Rightarrow t=0.97 \s

Time taken to reach maximum height is 0.97 seconds

s=ut+\frac{1}{2}at^2\\\Rightarrow s=9.6\times 0.97+\frac{1}{2}\times -9.8\times 0.97^2\\\Rightarrow s=4.7\ m

So, the stone would travel 4.7 m up

So, total height ball would fall is 4.7+12.8 = 17.5 m

s=ut+\frac{1}{2}at^2\\\Rightarrow 17.5=0t+\frac{1}{2}\times 9.8\times t^2\\\Rightarrow t=\sqrt{\frac{17.5\times 2}{9.8}}\\\Rightarrow t=1.89\ s

Time taken by the stone to travel 17.5 m is 1.89 seconds

3 0
3 years ago
An object moving with uniform acceleration has a velocity of 14.0 cm/s in the positive x-direction when its x-coordinate is 2.85
Lerok [7]
Though expressed in coordinate form, this is an example of linear motion. With the given, the acceleration can be solved using the following equation:

s = Vo*t + (1/2)*a*t^2

Where:

s = displacement = 7.85 cm
Vo = 14.0 cm/s
t = 3.15 s
a = ?

Substituting:

<span>7.85 = (14)*(3.15) + (1/2)*a*(3.15)^2
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3 0
3 years ago
Sound waves have two parts. The part of the wave where the particles of the medium are spread apart is called the _____. rarefac
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Rarefaction is the decrease in pressure of a medium, in which the density of the particles is reduced (they are "spread apart.") Compression is consequently the opposite, the point of highest pressure. Pitch amplitude refers to the intensity of the wave (the difference in pressure between the points of compression and those of rarefaction.
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3 years ago
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