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AysviL [449]
2 years ago
10

The weight of a body is 147N. what is its mass?

Physics
1 answer:
barxatty [35]2 years ago
5 0

<u>To find the mass, with only the weight</u>:

  ⇒ must consider the relationship between the mass and weight

     ⇒ (<em>in other words</em>) we must find the equation that has both the

         mass and weight

<u>Based on our physics knowledge, we know</u>:

 Weight=mass*gravitational_. acceleration

  • Weight: 147N
  • Gravitational Acceleration: 9.8 m/s²

<u>Now let's plug in the values, and solve</u>:

 147N = mass*9.8_.m/s^2\\mass = 15_.kg

<u>Answer: 15 kg</u>

Hope that helps!

<em>*as a note, if you use the gravitational acceleration as 10m/s², then the answer would be 14.7 kg</em>

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topjm [15]

Answer:

1.66 m/s

Explanation:

Work or kinetic energy = \frac{1}{2} mv^{2}

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v = 1.66 m/s

6 0
3 years ago
Halley's comet orbits the sun roughly once every 76 years. It comes very close to the surface of the Sun on its closest approach
Licemer1 [7]

Answer:

r1 = 5*10^10 m , r2 = 6*10^12 m

v1 = 9*10^4 m/s

From conservation of energy

K1 +U1 = K2 +U2

0.5mv1^2 - GMm/r1 = 0.5mv2^2 - GMm/r2

0.5v1^2 - GM/r1 = 0.5v2^2 - GM/r2

M is mass of sun = 1.98*10^30 kg

G = 6.67*10^-11 N.m^2/kg^2

0.5*(9*10^4)^2 - (6.67*10^-11*1.98*10^30/(5*10^10)) = 0.5v2^2 - (6.67*10^-11*1.98*10^30/(6*10^12))

v2 = 5.35*10^4 m/s

3 0
3 years ago
Describe the main energy transformations that occur when an apple falls from a tree? ​
blondinia [14]

Answer:

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Explanation:

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Sorry if im wrong

7 0
2 years ago
In 2004 astronomers reported the discovery of a large Jupiter-sized planet orbiting very close to the star HD 179949 (hence the
sp2606 [1]
  <span>I'll tell you how to do it but you must crunch the numbers. 

Use Kepler's 3rd Law 

T^2 = k R^3 

where k = 4(pi)^2/ GM 
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T =3.09 days = 266976 seconds 
R = (579,000,000km)/9 = 64333333.3 km 

a) 
Solve Kepler's 3rd Law for M. Your answer will be in kg 


b) 
mass of the sun = 1.98892 × 10^30 kilograms 
Form the ratio 
M(planet)/M(sun) </span>
6 0
3 years ago
How to change this to mega and giga prefixes?urgent .thankyou
Akimi4 [234]
3*10^{8} m = 3*10^{5} km = 3*10^{2} Mm = 3*10^{-1} Gm

Each increase in the prefix is a division by 1000.
6 0
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