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AysviL [449]
2 years ago
10

The weight of a body is 147N. what is its mass?

Physics
1 answer:
barxatty [35]2 years ago
5 0

<u>To find the mass, with only the weight</u>:

  ⇒ must consider the relationship between the mass and weight

     ⇒ (<em>in other words</em>) we must find the equation that has both the

         mass and weight

<u>Based on our physics knowledge, we know</u>:

 Weight=mass*gravitational_. acceleration

  • Weight: 147N
  • Gravitational Acceleration: 9.8 m/s²

<u>Now let's plug in the values, and solve</u>:

 147N = mass*9.8_.m/s^2\\mass = 15_.kg

<u>Answer: 15 kg</u>

Hope that helps!

<em>*as a note, if you use the gravitational acceleration as 10m/s², then the answer would be 14.7 kg</em>

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We have that the instantaneous power is

P=1239.6W

From the question we are told that

A 60 kg person runs up a 30° ramp

distance of 15 m up the ramp in 5.8 s.

t = 4.0 s?

Generally the equation for the Force  is mathematically given as

F-mgsin\theta=ma\\\\F-60*9.8*sin30=60*a

Where

s=ut+1/2at^2\\\\15=+0.5*a*5.8^2\\\\\a=0.891\\\\

Therefore

F=60(0.891)+294\\\\F=347.5

Where

v=u+at\\\\v=3.567

Now

P=f*v\\\\P=347.50*3.567

P=1239.6W

For more information on this visit

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A train travels at 270 km in 3 hours . what is the speed of the train?
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What is true about the velocity of sound waves in solids compared to air?
ivolga24 [154]
<h2>The correct option is (A)</h2>

Explanation:

Travels faster in solids because the particles are closer together.

The reason for the above statement is -

(i) Sound waves travel through the medium (solid, Liquid, and gas), more denser is the medium more is the speed of sound.

(ii) In solid, the particles are arranged very closely and tightly packed therefore the sound waves in solid have the fastest speed or travels fastest in comparison to liquid and gas.

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3 years ago
A spring with spring constant of 26 N/m is stretched 0.22 m from its equilibrium position. How much work must be done to stretch
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Answer:

1.503 J

Explanation:

Work done in stretching a spring = 1/2ke²

W = 1/2ke²........................... Equation 1

Where W = work done, k = spring constant, e = extension.

Given: k = 26 N/m, e = (0.22+0.12), = 0.34 m.

Substitute into equation 1

W = 1/2(26)(0.34²)

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W = 1.503 J.

Hence the work done to stretch it an additional 0.12 m = 1.503 J

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