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3 years ago

EASY! WILL REWARD BRAINLIEST!

Physics

1 answer:

lesya692 [45]3 years ago

6 0

Electrical current is defined as the flow of electric charge per unit time.

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A camera takes a properly exposed photo with a 4.0 mm diameter aperture and a shutter speed of 1/1000 s. If the photographer foc

hoa [83]

Answer:

option E

Explanation:

given,

diameter = 4 mm

shutter speed = 1/1000 s

diameter of aperture = ?

shutter speed = 1/250 s

exposure time to the shutter time

$E V = log_2(\dfrac{N^2}{t})$

N is the diameter of the aperture and t is the time of exposure

now,

$log_2(\dfrac{N^2}{t_1})=log_2(\dfrac{N^2}{t_2})$

$\dfrac{N_1^2}{t_1}=\dfrac{N_2^2}{t_2}$

inserting all the values

$\dfrac{4^2}{1000}=\dfrac{N_2^2}{250}$

N₂² = 4

N₂ = 2 mm

hence , the correct answer is option E

4 0

3 years ago

Which statement provides the most complete description of an object's motion?

vivado [14]

Answer:

A. The bird watcher followed the south trail a distance of five kilometers in 45 minutes.

5 0

2 years ago

An automobile to be transported by ship is raised 8.2m above the dock. If it's GPE is 63,405 J what is the car's mass?

Pepsi [2]

Answer:

m = 788.2[kg]

Explanation:

The potential energy of a body is defined as the product of mass by gravitational acceleration by height. And it can be calculated by means of the following equation.

$E_{pot}=m*g*h$

where:

Epot = potential energy = 63405 [J]

m = mass [kg]

g = gravity acceleration = 9.81[m/s²]

h = elevation = 8.2[m]

Now replacing:

$63405=m*9.81*8.2\\m=788.2[kg]$

5 0

3 years ago

How do electric field lines indicate the strength of the field?

Paha777 [63]

I am almost sure it it (c)

6 0

3 years ago

Read 2 more answers

A certain quantity of a liquid has a volume of 10cm at 20°C. Calculate its volume at 50°C, if it’s cubic expansivity is 10^(-3)

Pavel [41]

Answer:

10.3 cm³

Explanation:

From the question given above, the following data were obtained:

Original volume (V₁) = 10 cm³

Initial temperature (θ₁) = 20 °C

Final temperature (θ₂) = 50 °C

Cubic expansivity (γ) = 10¯³ K¯¹

Final volume (V₂) =?

γ = V₂ – V₁ / V₁(θ₂ – θ₁)

10¯³ = V₂ – 10 / 10( 50 – 20)

10¯³ = V₂ – 10 / 10(30)

10¯³ = V₂ – 10 / 300

Cross multiply

10¯³ × 300 = V₂ – 10

0.3 = V₂ – 10

Collect like terms

0.3 + 10 = V₂

10.3 = V₂

V₂ = 10.3 cm³

Thus, the volume at 50 °C is 10.3 cm³

6 0

2 years ago