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Mama L [17]
3 years ago
10

EASY! WILL REWARD BRAINLIEST!

Physics
1 answer:
lesya692 [45]3 years ago
6 0

Electrical current is defined as the flow of electric charge per unit time.

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Which would you expect to freeze faster pure water or salt solution why?
krek1111 [17]
Pure water.

A salt solution contains impurities whereas pure water will not contain any impurities.

Impurities increase the boiling point (freezing point) of a substance.

Thus, I would expect the pure water solution to freeze faster than the salt solution.
6 0
3 years ago
Why does the sun move across the sky
nasty-shy [4]
Hey there,

<em />Answer:

The sun appears to move across the sky but it is actually the earth which is orbiting around the sun.

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3 0
3 years ago
Read 2 more answers
A cyclist maintains a constant velocity of 6.1 m/s headed away from point A. At some initial time, the cyclist is 242 m from poi
KengaRu [80]

Answer:

553.1m

Explanation:

When an object moves at constant velocity we can express this movement like V=x/t, where V is the velocity, x is the displacement and t is the time spent on it.

In that way, the expression x=V.t give us the displacement from t=0s until t=51s, but we have to sum the initial distance from the point A.

x=242m +V.t = 242m + (6.1m/s x 51s) = 553.1m

7 0
3 years ago
According to the spectrum seen below, which set of photons were absorbed by the element?
Effectus [21]
The correct choice is ' D ' .

These are the numbers that are missing from the set of blocks at
the top, and also the bars missing from the graph in the middle.

I have no idea what the strip at the bottom labeled "full energy spectrum"
is trying to tell us.

5 0
3 years ago
Read 2 more answers
A dust particle with mass of 5.4×10−2 g and a charge of 2.3×10−6 C is in a region of space where the potential is given by V(x)=
user100 [1]

Answer:

1.6 m/s^2

Explanation:

Hello!

To calculate the acceleration we must know the electric field. The electric field and the potential are related by:

E = -\frac{dV}{dx} =- 2.6(\frac{V}{m^{2}})x + 8.1(\frac{V}{m^{3}})x^{2}

If the particle starts at 2.3m, the electric field is:

E = 36.869 V/m = 36.869 N/C

So, the force on the particle is:

F = q E =  2.3×10^−6 C * 36.869 N/C = 8.48 x 10^-5 N

And its acceleration is :

a = F/m =  8.48 x 10^-5 N / 5.4×10−5 kg = 1.57 m/s^2

Rounded to two significant figures:

1.6 m/s^2

6 0
3 years ago
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