The sum of four positive integers is 125. If you increase the first number by 4, decrease the second by 4, multiply the third by
4, and divide the fourth by 4, you produce four equal numbers. What is the smallest of the original numbers
1 answer:
Step-by-step explanation:
a + b + c + d = 125
a + 4 = b - 4 = 4c = d/4
a + 8 = b
a = b - 8
16c = d
b = 4c + 4
4a + 16 = d
b - 8 + 4c + 4 + c + 16c = 125
4c + 4 - 8 + 4c + 4 + c + 16c = 125
25c = 125
c = 5
d = 16c = 80
4a + 16 = d = 80
4a = 64
a = 16
b = a + 8 = 16 + 8 = 24
so, the numbers are
16, 24, 5, 80
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Step-by-step explanation:
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