The equation that can be used to determine when each cooler would contain the same amount of water is 4.5 + 0.1t = 7 + 0.25t
<h3>When the coolers would have the same amount of water?</h3>
Equation that can be used to determine the amount of water in the first cooler at time t : 4.5 + 0.1t
Equation that can be used to determine the amount of water in the second cooler at time t : 7 + 0.25t
Where t represents seconds
When they have the same amount of water, the two above equations would be equal
4.5 + 0.1t = 7 + 0.25t
Combine similar terms
7 - 4.5 = 0.1t - 0.25t
2.5 = 0.75t
Hence the equation that can be used to determine when each cooler would contain the same amount of water is 4.5 + 0.1t = 7 + 0.25t
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The cost to mail a 2-lb package is $7.
The cost to mail a 2-lb, 1 oz package is $7+$0.30(1).
That to mail a 2-lb, 2 oz package is $7+$0.30(2) = $7.60.
Following this pattern, the general formula is f(x) = $7 + $0.30x, where x represents the number of ounces OVER 2 lb.
Answer:
10a = 30
Step-by-step explanation:
By using elimination:
4a + 2z = 10
-2(3a + z) = -2(-10)
4a + 2z = 10
6a - 2z = 20
2z and -2z cancel out
10a = 30
a = 3
They are asking for 10a, so 10 (3) = 30.
Answer:
Hydrostatic Force = 35.28KN
Step-by-step explanation:
To solve this question, let's consider integrating the hydrostatic force from the top of the triangle to the bottom.
Formula for a thin horizontal slice of the triangle the force is;
δF=ρgxwδx
Where w is width of triangle; ρ is density of water and g is acceleration due to gravity
At depth x, the width of the triangle is w=2/3x.
Thus, F = (3,0)∫)ρgxwδx
=(2/3)ρg[(3,0)∫)x²δx]
= integrating, we have;
F = (2/3)ρg[(3³/3) - (0³/3)]
F = (2/5)ρg [27/3] = (2/5)(1000)(9.8)(9) = 35280 N = 35.28 KN
Answer:
higigj jo Dickenson g three-dimensional