How to understand the problem is like this:
Total Cost = Entrance Fee + Total Car cost
So we know that the Entrance Fee is $150...
Total Cost = $150 + Total Car cost
So we know that Anne bought 13 cars, each at $2,000...
Total Cost = $150 + ($2,000 x 13)
We multiply because each car is $2,000 and Anne bought 13 of them.
So it works out like this:
Total Cost = $150 + ($2,000 x 13)
Total Cost = $150 + (26000)
Total Cost = $26150
Answer:
Edwin wins by 1 sec
Step-by-step explanation:
Hope it helped you!
Answer:
Simple, no. This would not be enough.
Step-by-step explanation:
This is because you mentioned that there are 20 students and each of them needed 2 plates. So, there would need to be at least 40 plates. Forks seem irrelevant in this question but if the teacher has 8 plates in 1 box and another 8 in the second box, that would sum up to 16 plates that are available. And the fact that the box doesn't even include the other items, should hint the lack of items available for the students.
This question seemed worded differently. But tried my best. :)
F(x) = 18-x^2 is a parabola having vertex at (0, 18) and opening downwards.
g(x) = 2x^2-9 is a parabola having vertex at (0, -9) and opening upwards.
By symmetry, let the x-coordinates of the vertices of rectangle be x and -x => its width is 2x.
Height of the rectangle is y1 + y2, where y1 is the y-coordinate of the vertex on the parabola f and y2 is that of g.
=> Area, A
= 2x (y1 - y2)
= 2x (18 - x^2 - 2x^2 + 9)
= 2x (27 - 3x^2)
= 54x - 6x^3
For area to be maximum, dA/dx = 0 and d²A/dx² < 0
=> 54 - 18x^2 = 0
=> x = √3 (note: x = - √3 gives the x-coordinate of vertex in second and third quadrants)
d²A/dx² = - 36x < 0 for x = √3
=> maximum area
= 54(√3) - 6(√3)^3
= 54√3 - 18√3
= 36√3.
