Answer:
1.3cm
Step-by-step explanation:
The scale from the actual coin to the photo is 8 mm to 2 cm In the photo,
converting 8mm to cm = 0.8 cm
using ratio and proportion,
if 2cm = 3.25 cm
then 0.8cm = ? less
if less then more devides.
thus ; (0.8cm ÷2cm ) × 3.25cm =
( 0.4) × 3.25cm = 1.3cm
therefore the distance across the actual coin is 1.3cm.
Answer:
Step-by-step explanation:
Answer:
y - 4 = -2/3 (x + 1)
Step-by-step explanation:
y2 - y1 / x2 - x1 -2 - 4 / 8 - (-1) -6/9 = -2/3
y - 4 = -2/3 (x + 1)
There was 3000 general admission tickets sold and 500 kid ticket sold.
How did I get this?
First, we need to see what information we have.
$2.50 = General admission tickets = (G)
$0.50 = kids tickets = (K)
There were 6x as many general admission tickets sold as kids. G = 6K
We need two equations:
G = 6K
$2.50G + $.50K = $7750
Since, G = 6K we can substitute that into the 2nd equation.
2.50(6K) + .50K = 7750
Distribute 2.50 into the parenthesis
15K + .50K = 7750
combine like terms
15.50K = 7750
Divide both sides by 15.50, the left side will cancel out.
K = 7750/15.50
K = 500 tickets
So, 500 kid tickets were sold.
Plug K into our first equation (G = 6k)
G = 6*500
G = 3000 tickets
So, 3000 general admission tickets were sold,
Let's check this:
$2.50(3000 tickets) = $7500 (cost of general admission tickets)
$.50(500 tickets) = $250 (cost of general admission tickets)
$7500 + $250 = $7750 (total cost of tickets)
