Question

What is the solubility of sodium nitrate at 95º C in g/ 100 mL of water?

Answer 1

The solubility of sodium nitrate at 95º C in g/ 100 mL of water is 448.21.

Equation :

To calculate the solubility

Using formula,

Solubility = mass of the compound / mass of the solvent  

Thus,

Known data is :

mass of the compound, sodium nitrate = 84.994 g/mol

mass of the solvent, water = 18.015 g/mol

C = 84.994 g/mol / 18.015 g/mol

C = 4.718 g/mol

By the temperature 95ºC

So,

C = 4.718 g/mol x 95ºC

C = 448.21 g/ 100 mL

Solubility :

The maximum amount of the sample that will dissolve in a given amount of solvent at a given temperature is referred to as its solubility. Different substances have very different solubilities, which is a characteristic of a particular solute-solvent combination.

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