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mojhsa [17]
1 year ago
11

there are 6 studenjts in the class. one of them is to be selcted as the best studen and another student is to be selceted as a r

unner-up. how mant different ways can this be done?
Mathematics
1 answer:
Zarrin [17]1 year ago
5 0

As per the combination method, there are 15 different ways are possible for this situation.

Combination method:

Combination method also known as NCR is a formula of combination and arrangement, where the object's order does not matter so much.

Given,

Here we have to find the number of ways to be selected as the best student and another student is to be selected as a runner-up among the 6 students.

Here we know that that the value of

Total number of students = 6

Best student = 1

Runner - up = 1

So, as per the NCR formula, the value of n = 6 and the value of r = 2

Then the possible combinations are calculated as,

=> ⁶C₂ = 6! / 2!(6 - 2)!

=> ⁶C₂ = 6!/2!4!

=>⁶C₂ = 15

Therefore, the resulting number of ways is 15.

To know more about Combination method here.

brainly.com/question/28998705

#SPJ4

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Answer:

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Step-by-step explanation:

Simplify the following:

48/6 - 10/3

Hint: | Reduce 48/6 to lowest terms. Start by finding the GCD of 48 and 6.

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Hint: | Subtract 10 from 24.

| 2 | 4

- | 1 | 0

| 1 | 4:

Answer:  14/3

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