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steposvetlana [31]
3 years ago
12

5. 2x+y=4 ty 2 -20 2 2

Mathematics
1 answer:
ZanzabumX [31]3 years ago
6 0

Answer: y= (-2)x + 4

graph:

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carl used 2 1/2 cup of peanuts for every 1/2 cups of raisins when making a mix. enter the number of cups of peanuts carl uses fo
ale4655 [162]

Answer:

5 cups of peanuts

Step-by-step explanation:

My reasoning is if 1/2 cup of raisins is 2 1/2 cup of peanuts, you basically double the amount. So 1/2 becomes 1 cup and 2 1/2 becomes 5 cups. So 5 cups of peanuts for 1 cup of raisins.

3 0
4 years ago
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-5 + 4 on a number line
alexandr402 [8]
-1 is the answer homie
7 0
3 years ago
There is a bag filled with 5 blue, 2 red and 3 green marbles,
nikdorinn [45]

Answer:

0.62

Step-by-step explanation:

There are a total of 10 marbles in the bag.

P(blue and not blue) = 5/10 × 5/10 = 25/100

P(red and not red) = 2/10 × 8/10 = 16/100

P(green and not green) = 3/10 × 7/10 = 21/100

P = 25/100 + 16/100 + 21/100

P = 62/100

P = 0.62

Alternatively, you can calculate it this way:

P(both blue) = (5/10)² = 25/100

P(both red) = (2/10)² = 4/100

P(both green) = (3/10)² = 9/100

P = 1 − (25/100 + 4/10 + 9/100)

P = 1 − 38/100

P = 62/100

P = 0.62

5 0
3 years ago
Tony spent $60 on video games , each video game cost $6 . how many video games did tony buy
saveliy_v [14]

Answer:

10

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
For which of the following counts would a binomial probability model be reasonable? a. The number of traffic tickets written by
timama [110]

Answer:

c. The number of 7's in a randomly selected set of five random digits from a table of random digits.

True, for this case we have a value fixed for n =5 and the probability is defined for each number 1/10 assuming numbers (0,1,2,3,4,5,6,7,8,9) so then the random variable "The number of 7's in a randomly selected set of five random digits" can be modelled with the binomial probability function.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n, p)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

The conditions to apply this distribution is that we have the parameters fixed n and p.

Let's analyze one by one the possible solutions:

a. The number of traffic tickets written by each police officer in a large city during one month.

False, the number of traffic tickets written by each police is not a fixed amount always, so then the value of n change and we can't apply a binomial model for this case.

b. The number of hearts in a hand of five cards dealt from a standard deck of 52 cards that has been thoroughly shuffled.

False, not all the hands of size 5 are equal and since we can't ensure this condition then the binomial model not apply for this case

c. The number of 7's in a randomly selected set of five random digits from a table of random digits.

True, for this case we have a value fixed for n =5 and the probability is defined for each number 1/10 so then the random variable "The number of 7's in a randomly selected set of five random digits" can be modelled with the binomial probability function.

d. The number of phone calls received in a one-hour period.

False, the number of phone calls change by the hour and is not always fixed so then we don't have a valu for n, and the binomial model not applies for this case.

e. All of the above.

False option C is correct.

5 0
3 years ago
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