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olga nikolaevna [1]
1 year ago
5

Emmit says the dilation can be represented by (1/2X, 1\2Y)Emily says the dilation can be represented by(1\3X, 1\3Y)Who is correc

t and why

Mathematics
1 answer:
schepotkina [342]1 year ago
3 0

In the triangle LJK, the length of side LK=18.

In the triangle L'J'K', the length of side L'K'=6

Therefore,

L^{\prime}K^{\prime}=\frac{1}{3}LK=\frac{1}{3}\times18=6

Therefore, the scale factor for dilation is 1/3.

So, the dilation can be represented as

\frac{1}{3}X,\frac{1}{3}Y

So, Emily's statement is correct.

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Willie took out a simple interest loan of $6,000 at 10% interest for 24 months. His monthly payment is $276.60. After 4 payments
pychu [463]
1.000 dollars and 52 cents

4 0
2 years ago
Y = 3x^2 - 4x<br> 27 + y = 14x
Hatshy [7]

Step-by-step explanation:

move the 27 to the other side of the equation like this

y = 14x - 27

use this equation and substitute it into the y value of the first equation

4 0
2 years ago
1
Mariana [72]

Answer:

x = 6

Step-by-step explanation:

∠ DBC + ∠ ABC = ∠ ABD , substitute values

5x - 4 + 8x - 3 = 79

13x + 1 = 79 ( subtract 1 from both sides )

13x = 78 ( divide both sides by 13 )

x = 6

8 0
3 years ago
what are the steps to answer this question? Jeff is baking a cake. The recipe says that he has to mix 32 grams of powder to the
Deffense [45]
Well what I would do first is to divide 128 by 32 which I do believe gets you 4. So now you know that 1 cup of powder can make 4 servings. So you now know that each serving only requires 1/4 cup of the powder.

So now we know Jeff went over so now we have Jeff added 2/3 and he only needs 1/4. I would now make them both equivalent by multiplying the numerator and denominator of 2/3 by 4 and the same for 1/4 but instead by 4 multiply it by 3 which you would get 2/3=8/12 and 1/4=3/12. Now subtract the two to get your answer.

8/12-3/12=5/12

Answer: He went over and he needs to remove 5/12 of the cup
5 0
2 years ago
I need help finding the area
aniked [119]
<h3>Given :</h3>
  • Base of triangle = 7 yd
  • Height of triangle = 10 yd

\\  \\

<h3>To find:</h3>
  • Area of triangle

\\  \\

We know:-

When base and height of triangle is given we use this formula:

\bigstar \boxed{ \rm Area \: of \: triangle =  \frac{base \times height}{2} }

\\  \\

So:-

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{base \times height}{2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 10}{2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times2 }{2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times\cancel2 }{\cancel2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times1 }{1}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =7 \times 5

\\  \\

\dashrightarrow \bf \: Area \: of \: triangle =35 {yd}^{2}  \\

\\  \\

\therefore  \underline{\textsf{ \textbf {\: Area \: of \: triangle = \red{35}}} {  \red{\bf{yd} }^{ \red2} }}

\\  \\

<h3>know more :-</h3>

\small\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf \small{Formulas\:of\:Areas:-}}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Base\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}\end{gathered}\end{gathered}]

7 0
1 year ago
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