If you sold 2000 in the first week and a hundred percent more second week it would be 2000
Answer:
I need more information
Step-by-step explanation:
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Answer with explanation:</h2>
Given : In a restaurant, the proportion of people who order coffee with their dinner is p.
Sample size : n= 144
x= 120
![\hat{p}=\dfrac{x}{n}=\dfrac{120}{144}=0.83333333\approx0.8333](https://tex.z-dn.net/?f=%5Chat%7Bp%7D%3D%5Cdfrac%7Bx%7D%7Bn%7D%3D%5Cdfrac%7B120%7D%7B144%7D%3D0.83333333%5Capprox0.8333)
The null and the alternative hypotheses if you want to test if p is greater than or equal to 0.85 will be :-
Null hypothesis :
[ it takes equality (=, ≤, ≥) ]
Alternative hypothesis :
[its exactly opposite of null hypothesis]
∵Alternative hypothesis is left tailed, so the test is a left tailed test.
Test statistic : ![z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B%5Chat%7Bp%7D-p%7D%7B%5Csqrt%7B%5Cdfrac%7Bp%281-p%29%7D%7Bn%7D%7D%7D)
![z=\dfrac{0.83-0.85}{\sqrt{\dfrac{0.85(1-0.85)}{144}}}\\\\=-0.561232257678\approx-0.56](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B0.83-0.85%7D%7B%5Csqrt%7B%5Cdfrac%7B0.85%281-0.85%29%7D%7B144%7D%7D%7D%5C%5C%5C%5C%3D-0.561232257678%5Capprox-0.56)
Using z-vale table ,
Critical value for 0.05 significance ( left-tailed test)=-1.645
Since the calculated value of test statistic is greater than the critical value , so we failed to reject the null hypothesis.
Conclusion : We have enough evidence to support the claim that p is greater than or equal to 0.85.
The First two coefficients are positive because they are on the positive side of the y-axis.
The Last two are on the negative side of the y-axis. B is the closest to zero as the wider the graph is, the lower the coefficient is.
The coefficient with the greatest value would be D
Answer:
i believe the answer is 2,340
Step-by-step explanation: