Answer:
Explanation:
<u>1) Calculate the volume of the water in the tank.</u>
- Area of the base of the tank: B = 7 ft × 4 ft = 28 ft²
- Height of the tank: H = 9 in = 9 in × 1 ft / 12 in = 0.75 ft
- Volume of the tank: V = area of the base × height = B × H = 28 ft² × 0.75 ft = 21 ft³.
<u>2) Calculate the weight of 21 ft³ of water.</u>
Since this is not a chemistry question but a math question, I will not use the fomula of density but set a proportion with one unknown:
- 62.4 lb / 1 ft³ = x / 21 ft³
Solve for x:
- x = 21 ft³ × 64 lb / ft³ = 1,310.4 lb.
So, rounding to the next integer, the water in the tank weighs 1,310 pounds, when it is full.
Answer:
x=10°
y = 12°
Step-by-step explanation:
<TSV = 5x + 4x = 90°
=> 9x = 90°
Divide by 9,
x = 10°
<RSU = 10y + 10° + 5x = 180°
=> 10y + 10° + 5*10° = 180°
=> 10y + 10° + 50° = 180°
=> 10y + 60° = 180°
Subtract 60° on both sides,
10y = 180° - 60° = 120°
Divide by 10,
y = 120° / 10 = 12°
Answer:
n=13
Step-by-step explanation:
3n-6=33
Add 6 to both sides
3n=39
Divide both sides by 3
n=13
Answer:
a = 33 degrees, b = 147 degrees
Step-by-step explanation:
The sum of all the angles in a triangle is 180 degrees, and to solve for the angle on the other side of 109 degrees is 71 degrees, so to solve for a, have 180 minus 71 and 76. Then the sum of 71 and 76 is angle b since its the result of a subtracting from 180.
