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andreyandreev [35.5K]
2 years ago
13

The price of all rail season tickets to London increased by 4%. The price of a rail season ticket from Cambridge to London incre

ased by 121.60. work out the price before this increase.
Mathematics
1 answer:
kirill115 [55]2 years ago
8 0
Percentage increase in the rate of all rail season tickets to London = 4%
Price of the rail ticket from Cambridge to London increased by = 121.60
Let us assume the price before the increase in the fare = x
Then
4% * x = 121.60 dollars
(4/100) * x = 121.60 dollars
x/25 = 121.60 dollars
x = 25 * 121.60 dollars
   = 3040 dollars
So the price of the ticket from Cambridge to London before the increase in price was 3040. I hope the procedure is simple enough for you to understand.
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Factor (z-5)(z+4)=52​
Ipatiy [6.2K]

Good Afternoon! Here is your answer step by step!

Let's solve your equation step-by-step.

(z−5)(z+4)=52

Step 1: Simplify both sides of the equation.

z2−z−20=52

Step 2: Subtract 52 from both sides.

z2−z−20−52=52−52

z2−z−72=0

Step 3: Factor left side of equation.

(z+8)(z−9)=0

Step 4: Set factors equal to 0.

z+8=0 or z−9=0

z=−8 or z=9

Answer:

z=−8 or z=9

Have a blessed day! ❤

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2 years ago
Solve for x in the equation x squared + 2 x + 1 = 17.
Papessa [141]

Answer:

x = - 1 + \sqrt{17}\\and\\x = - 1 - \sqrt{17}\\

Step-by-step explanation:

given equation

x^2 +2x +1 = 17

subtracting 17 from both sides

x^2 +2x +1 = 17\\x^2 +2x +1 -17= 17-17\\x^2 +2x - 16 = 0\\

the solution for quadratic equation

ax^2 + bx + c = 0 is given by

x = x = -b + \sqrt{b^2 - 4ac} /2a \\\\and \ \\-b - \sqrt{b^2 - 4ac} /2a

________________________________

in our problem

a = 1

b = 2

c = -16

x =( -2 + \sqrt{2^2 - 4*1*-16}) /2*1 \\x =( -2 + \sqrt{4  + 64}) /2\\x =( -2 + \sqrt{68} )/2\\x = ( -2 + \sqrt{4*17} )/2\\x =  ( -2 + 2\sqrt{17} )/2\\x = - 1 + \sqrt{17}\\and\\\\x = - 1 - \sqrt{17}\\

thus value of x is

x = - 1 + \sqrt{17}\\and\\x = - 1 - \sqrt{17}\\

3 0
2 years ago
Please help me with this
aalyn [17]

Answer:

200-225

Step-by-step explanation:

trust me haha

4 0
2 years ago
Find equation of the line that contains the point (4,-2) and is perpendicular to the line y= _2x+8
xz_007 [3.2K]

Answer:

y = 1/2x - 4

Step-by-step explanation:

If two lines are perpendicular to each other, they have opposite slopes.

The first line is y = -2x + 8. Its slope is -2. A line perpendicular to this one will  have a slope of 1/2.

Plug this value (1/2) into your standard point-slope equation of y = mx + b.

y = 1/2x + b

To find b, we want to plug in a value that we know is on this line: in this case, it is (4, -2). Plug in the x and y values into the x and y of the standard equation.

-2 = 1/2(4) + b

To find b, multiply the slope and the input of x (4)

-2 = 2 + b

Now, subtract 2 from both sides to isolate b.

-4 = b

Plug this into your standard equation.

y = 1/2x - 4

This equation is perpendicular to your given equation (y = -2x + 8) and contains point (4, -2)

Hope this helps!

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2 years ago
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