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Usimov [2.4K]
1 year ago
12

60 PTS, BRAINLIEST, 5-STAR, THANKS.

Mathematics
1 answer:
kakasveta [241]1 year ago
5 0

Step-by-step explanation:

Add everything and then equate it to 360 and when you have found x, substitute it in A and B

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I need help finding the X in these equations
krek1111 [17]

Answer:

For D I believe it would be 6

Step-by-step explanation:

I believe 6 because is you do 108÷18 you get 6 and then it would be 6/108 = 7/18 which is true.

Might not be correct and I don't know the others sorry!

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7(-2k+4)-6=7k-20 what is the answer
lord [1]
The answer to this equation would be k=2
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The price decreased by nine dollars
suter [353]

Answer: -9

Step-by-step explanation: it is a negative because it is minus 9$ from the price just like adding -9

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Read 2 more answers
A $104.000 selling price with $24000 down at 8 1/2% for 25 years results in a monthly payment of
romanna [79]
*******************************************************
(See attached formula)
Loan Principal = 104,000 - 24,000 = 80,000
rate = 8.5 / 1,200  = <span> <span> <span> 0.0070833333 </span> </span> </span>
time = 25 years = 300 months

Monthly Payment = <span> <span> 0.0070833333 </span> + </span><span> <span> [ 0.0070833333 / ((1</span></span><span>.0070833333)^300 -1)) ] *principal
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Monthly Payment = <span>0.0070833333 + </span><span> [ 0.0070833333 / (</span><span> </span> <span> <span> <span> 8.3104129461 </span> </span> </span> -1)] * 80,000
Monthly Payment = 0.0070833333 + [ 0.0070833333 / ( 7.3104129461)] * 80,000
Monthly Payment = (0.0070833333 + <span> <span> <span> 0.00096893750767) * 80,000
</span></span></span>Monthly Payment = <span> <span> <span> 0.00805227080767 </span> </span> </span> * 80,000
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Source:
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3 0
3 years ago
Use polar coordinates to find the volume of the given solid. Inside both the cylinder x2 y2 = 1 and the ellipsoid 4x2 4y2 z2 = 6
Anton [14]

The Volume of the given solid using polar coordinate is:\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta

V= \frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta

<h3>What is Volume of Solid in polar coordinates?</h3>

To find the volume in polar coordinates bounded above by a surface z=f(r,θ) over a region on the xy-plane, use a double integral in polar coordinates.

Consider the cylinder,x^{2}+y^{2} =1 and the ellipsoid, 4x^{2}+ 4y^{2} + z^{2} =64

In polar coordinates, we know that

x^{2}+y^{2} =r^{2}

So, the ellipsoid gives

4{(x^{2}+ y^{2)} + z^{2} =64

4(r^{2}) + z^{2} = 64

z^{2} = 64- 4(r^{2})

z=± \sqrt{64-4r^{2} }

So, the volume of the solid is given by:

V= \int\limits^{2\pi}_ 0 \int\limits^1_0{} \, [\sqrt{64-4r^{2} }- (-\sqrt{64-4r^{2} })] r dr d\theta

= 2\int\limits^{2\pi}_ 0 \int\limits^1_0 \, r\sqrt{64-4r^{2} } r dr d\theta

To solve the integral take, 64-4r^{2} = t

dt= -8rdr

rdr = \frac{-1}{8} dt

So, the integral  \int\ r\sqrt{64-4r^{2} } rdr become

=\int\ \sqrt{t } \frac{-1}{8} dt

= \frac{-1}{12} t^{3/2}

=\frac{-1}{12} (64-4r^{2}) ^{3/2}

so on applying the limit, the volume becomes

V= 2\int\limits^{2\pi}_ {0} \int\limits^1_0{} \, \frac{-1}{12} (64-4r^{2}) ^{3/2} d\theta

=\frac{-1}{6} \int\limits^{2\pi}_ {0} [(64-4(1)^{2}) ^{3/2} \; -(64-4(2)^{0}) ^{3/2} ] d\theta

V = \frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta

Since, further the integral isn't having any term of \theta.

we will end here.

The Volume of the given solid using polar coordinate is:\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta

Learn more about Volume in polar coordinate here:

brainly.com/question/25172004

#SPJ4

3 0
2 years ago
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