Answer:
For D I believe it would be 6
Step-by-step explanation:
I believe 6 because is you do 108÷18 you get 6 and then it would be 6/108 = 7/18 which is true.
Might not be correct and I don't know the others sorry!
The answer to this equation would be k=2
Answer: -9
Step-by-step explanation: it is a negative because it is minus 9$ from the price just like adding -9
*******************************************************
(See attached formula)
Loan Principal = 104,000 - 24,000 = 80,000
rate = 8.5 / 1,200 =
<span>
<span>
<span>
0.0070833333
</span>
</span>
</span>
time = 25 years = 300 months
Monthly Payment = <span>
<span>
0.0070833333
</span>
+ </span><span>
<span>
[ 0.0070833333
/ ((1</span></span><span>.0070833333)^300 -1)) ] *principal
</span>
Monthly Payment = <span>0.0070833333
+ </span><span>
[ 0.0070833333
/ (</span><span>
</span>
<span>
<span>
<span>
8.3104129461
</span>
</span>
</span>
-1)] * 80,000
Monthly Payment = 0.0070833333
+
[ 0.0070833333
/ ( 7.3104129461)] * 80,000
Monthly Payment = (0.0070833333
+
<span>
<span>
<span>
0.00096893750767) * 80,000
</span></span></span>Monthly Payment =
<span>
<span>
<span>
0.00805227080767
</span>
</span>
</span>
* 80,000
Monthly Payment =
<span>
<span>
<span>
644.18
Source:
http://www.1728.org/calcloan.htm
</span></span></span>
The Volume of the given solid using polar coordinate is:![\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B6%7D%20%5Cint%5Climits%5E%7B2%5Cpi%7D_%20%7B0%7D%20%5B%2860%29%20%5E%7B3%2F2%7D%20%5C%3B%20-%2864%29%20%5E%7B3%2F2%7D%20%5D%20d%5Ctheta)
V= ![\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B6%7D%20%5Cint%5Climits%5E%7B2%5Cpi%7D_%20%7B0%7D%20%5B%2860%29%20%5E%7B3%2F2%7D%20%5C%3B%20-%2864%29%20%5E%7B3%2F2%7D%20%5D%20d%5Ctheta)
<h3>
What is Volume of Solid in polar coordinates?</h3>
To find the volume in polar coordinates bounded above by a surface z=f(r,θ) over a region on the xy-plane, use a double integral in polar coordinates.
Consider the cylinder,
and the ellipsoid, 
In polar coordinates, we know that

So, the ellipsoid gives

4(
) +
= 64
= 64- 4(
)
z=± 
So, the volume of the solid is given by:
V= ![\int\limits^{2\pi}_ 0 \int\limits^1_0{} \, [\sqrt{64-4r^{2} }- (-\sqrt{64-4r^{2} })] r dr d\theta](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%7B2%5Cpi%7D_%200%20%5Cint%5Climits%5E1_0%7B%7D%20%5C%2C%20%5B%5Csqrt%7B64-4r%5E%7B2%7D%20%7D-%20%28-%5Csqrt%7B64-4r%5E%7B2%7D%20%7D%29%5D%20r%20dr%20d%5Ctheta)
= 
To solve the integral take,
= t
dt= -8rdr
rdr = 
So, the integral
become
=
= 
=
so on applying the limit, the volume becomes
V= 
=![\frac{-1}{6} \int\limits^{2\pi}_ {0} [(64-4(1)^{2}) ^{3/2} \; -(64-4(2)^{0}) ^{3/2} ] d\theta](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B6%7D%20%5Cint%5Climits%5E%7B2%5Cpi%7D_%20%7B0%7D%20%5B%2864-4%281%29%5E%7B2%7D%29%20%5E%7B3%2F2%7D%20%5C%3B%20-%2864-4%282%29%5E%7B0%7D%29%20%5E%7B3%2F2%7D%20%5D%20d%5Ctheta)
V = ![\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B6%7D%20%5Cint%5Climits%5E%7B2%5Cpi%7D_%20%7B0%7D%20%5B%2860%29%20%5E%7B3%2F2%7D%20%5C%3B%20-%2864%29%20%5E%7B3%2F2%7D%20%5D%20d%5Ctheta)
Since, further the integral isn't having any term of
.
we will end here.
The Volume of the given solid using polar coordinate is:![\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B6%7D%20%5Cint%5Climits%5E%7B2%5Cpi%7D_%20%7B0%7D%20%5B%2860%29%20%5E%7B3%2F2%7D%20%5C%3B%20-%2864%29%20%5E%7B3%2F2%7D%20%5D%20d%5Ctheta)
Learn more about Volume in polar coordinate here:
brainly.com/question/25172004
#SPJ4