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liraira [26]
3 years ago
5

7 3 × √ 7 as a single power of 7

Mathematics
2 answers:
Anuta_ua [19.1K]3 years ago
7 0

Answer:

  • See the steps below

Step-by-step explanation:

  • 7^3*\sqrt{7} =
  • 7^3*7^{1/2}=
  • 7^{3+1/2}=
  • 7^{3.5}
andrezito [222]3 years ago
4 0

Step-by-step explanation:

first \:  take \:  square \:  root \:  of \:   \sqrt{7}  then  \: multiply  \: by  \: 73 \:  and  \: you  \: will  \: get \:  answer

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Answer:

$59.4

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suppose you are trying to increase your coin collection to at least 500 coins. How many coins do you need if you already have a
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Marrisa added 1.56 and 13.47. She got 29.07. What mistake could Marrisa have made?
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She hadn't lined up the decimal points correctly.

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Correct way:

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A Gardener has 2 tulip bulb, 45 tomato plants, 108 rose bushes, and 126 herd seedling to plant in the city garden. He want each
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Answer: <em> 9\ rows</em>

Step-by-step explanation:

<h3> <em>The complete exercise is:"A gardener has 27 tulip bulbs, 45 tomato plants, 108 rose bushes, and 126 herb seedlings to plant in the city garden. He wants each row of the garden to have the same number of each kind of plant. What is the greatest number of rows that the gardener can make if he uses all the plants?"</em></h3><h3 />

The first step to solve the exercise is to find the Greatest Common Factor (GCF) between 27, 45, 108 and 126.

You can follow these steps in order to find the GCF:

1. You must decompose 27, 45, 108 and 126into their prime factors:

27=3*3*3=3^3\\\\45=3*3*5=3^2*5\\\\108=2*2*3*3*3=2^2*3^3\\\\126=2*3*3*7=2*3^2*7

2. You must multiply the commons with the lowest exponents. Then:

<em>GCF=3^2\\\\GCF=9</em>

Therefore, the greatest number of rows that the gardener can make if he uses all the plants is:

9\ rows

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