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2 years ago

What is 17/100 simplest form?

Mathematics

2 answers:

Natasha_Volkova [10]2 years ago

7 0

17/100 this fraction cannot be simplified

lapo4ka [179]2 years ago

5 0

That is the simplest form.

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Trenton and Maria record how much dry food their pets eat on average each day.• Trenton's pet: 4/5 cup of dry food• Maria's pet:

Phoenix [80]

6.3 many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks

<u>Step-by-step explanation:</u>

We have , Trenton and Maria record how much dry food their pets eat on average each day.• Trenton's pet: 4/5 cup of dry food• Maria's pet: 1.25 cups of dry food. Based on these averages . We need to find how many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks . We need to find how much they eat for 14 days as:

Trenton's pet: 4/5 cup of dry food•

With 4/5 per day , for 14 days :

⇒ $14(\frac{4}{5} )$

⇒ $14(0.8 )$

⇒ $11.2$

Maria's pet: 1.25 cups of dry food.

With 1.25 per day , for 14 days :

⇒ $14(1.25 )$

⇒ $17.5$

Subtracting Maria's - Trenton's :

⇒ $17.5-11.2=6.3$

That means , 6.3 many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks

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3 years ago

I NEED HELP ASAP PLEASE GIVING BRAINLIEST!!

Salsk061 [2.6K]

Answer:

35 more video games

Step-by-step explanation:

40 times 3 and then substract 85

120-85=35

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2 years ago

Finding area of circle with radius , giving brainliest :)) pls help asap

Schach [20]

Answer:

number 2 is the answer or 4*pi inches² or 12.6

Step-by-step explanation:

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2 years ago

5x8(34-21+62)•56% 628^6 53%•927

sdas [7]

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3 years ago

Read 2 more answers

In general, the probability that a blood donor has Type A blood is 0.40.Consider 8 randomly chosen blood donors, what is the pro

postnew [5]

Answer:

The probability that more than half of them have Type A blood in the sample of 8 randomly chosen donors is P(X>4)=0.1738.

Step-by-step explanation:

This can be modeled as a binomial random variable with n=8 and p=0.4.

The probability that k individuals in the sample have Type A blood can be calculated as:

$P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{8}{k} 0.4^{k} 0.6^{8-k}\\\\\\$

Then, we can calculate the probability that more than 8/2=4 have Type A blood as:

$P(X>4)=P(X=5)+P(X=6)+P(X=7)+P(X=8)\\\\\\P(x=5) = \dbinom{8}{5} p^{5}(1-p)^{3}=56*0.0102*0.216=0.1239\\\\\\P(x=6) = \dbinom{8}{6} p^{6}(1-p)^{2}=28*0.0041*0.36=0.0413\\\\\\P(x=7) = \dbinom{8}{7} p^{7}(1-p)^{1}=8*0.0016*0.6=0.0079\\\\\\P(x=8) = \dbinom{8}{8} p^{8}(1-p)^{0}=1*0.0007*1=0.0007\\\\\\\\P(X>4)=0.1239+0.0413+0.0079+0.0007=0.1738$

3 0

3 years ago