The reaction corresponds to the combustion of propane (C3H8). The balanced reaction is:
C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g)
The reaction enthalpy is given as:
ΔHrxn = ∑nΔH°f(products) - ∑ nΔH°f(reactants)
= [3ΔH°f(CO2(g)) + 4ΔH°f(H2O(g)] - [1ΔH°f(C3H8(g)) + 5ΔH°f(O2(g)]
= [3(-393.5) + 4(-241.8)] - [-103.9 + 5(0)] = -2043.8 kJ
The enthalpy for the combustion of propane is -2044 kJ
The most common organic acids are the carboxylic acids
Energy and mass have not been created, the water has simply been changed to a different form, but it is still present, and could be condense down into the same form with the same mass.
Answer:
The rate law is rate = k[NO][O₃]
Option E) is the right answer.
Explanation:
Hi there!
For this generic reaction:
A + B → products
the rate law will be:
rate = k[A]ⁿ[B]ᵃ
this reaction is n-order in A and a-order in B. The overall reaction is the sum of the orders of each reactant, in this case:
Overall order of the reaction = n + a
In our problem, we know that the reaction is first order in O₃ and second order overall. Then:
Overall order of the reaction = Order in NO + Order in O₃
2 = n + 1
2 - 1 = n
n = 1
Then, the reaction is first order in NO and first order in O₃.
The rate law will be:
rate = k[NO][O₃]
The right answer is the option E).
