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andrezito [222]
3 years ago
13

Consider the formation of nitrogen dioxide and oxygen: NO(g)+O3(g)⇌NO2(g)+O2(g) The reaction is first order in O3 and second ord

er overall. What is the rate law? (A) rate=k[NO]2[O3]2(B) rate=k[NO][O3]2(C) rate=k[O3](D) rate=k[NO](E) rate=k[NO][O3](G) rate=k[NO]2[O3]
Chemistry
1 answer:
Leno4ka [110]3 years ago
3 0

Answer:

The rate law is rate = k[NO][O₃]

Option E) is the right answer.

Explanation:

Hi there!

For this generic reaction:

A + B → products

the rate law will be:

rate = k[A]ⁿ[B]ᵃ

this reaction is n-order in A and a-order in B. The overall reaction is the sum of the orders of each reactant, in this case:

Overall order of the reaction = n + a

In our problem, we know that the reaction is first order in O₃ and second order overall. Then:

Overall order of the reaction = Order in NO + Order in O₃

2 = n + 1

2 - 1 = n

n = 1

Then, the reaction is first order in NO and first order in O₃.

The rate law will be:

rate = k[NO][O₃]

The right answer is the option E).

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Gamma Ray's have the highest frequency.

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sasho [114]

Answer: Y and Z. It's D.

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3 0
3 years ago
how many grams of calcium oxide will be produced in a closed vessel containing 20.0 kg of calcium and 20.0 kg of oxygen gas if t
sergejj [24]

Answer:

27984.1311 g  

Explanation:

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

<u>For calcium :- </u>

Mass of calcium = 20.0 kg = 20000 g ( 1 kg = 1000 g )

Molar mass of calcium = 40.078 g/mol

Thus,

Moles= \frac{20000\ g}{40.078\ g/mol}

Moles\ of\ calcium= 499.0269\ mol

<u>For oxygen gas :- </u>

Mass of oxygen gas = 20.0 kg = 20000 g ( 1 kg = 1000 g )

Molar mass of oxygen gas = 31.999 g/mol

Thus,

Moles= \frac{20000\ g}{31.999\ g/mol}

Moles\ of\ oxygen\ gas= 625.0195\ mol

According to the given reaction:

2Ca+O_2\rightarrow 2CaO

2 moles of calcium reacts with 1 moles of oxygen gas

Also,

1 mole of calcium react with 1/2 mole of oxygen gas

So,

499.0269 mole of calcium react with \frac{1}{2}\times 499.0269 mole of oxygen gas

Moles of oxygen gas = 249.5135 moles

Available moles of oxygen gas = 625.0195 moles

Limiting reagent is the one which is present in small amount. Thus, calcium is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

2 moles of calcium produces 2 moles of calcium oxide

So,

1 mole of calcium produces 1 mole of calcium oxide

Also,

499.0269 mole of calcium produces 499.0269 mole of calcium oxide

Moles of calcium oxide = 499.0269 moles

Molar mass of calcium oxide = 56.0774 g/mol

Mass of calcium oxide = Moles × Molar mass = 499.0269 × 56.0774 g = 27984.1311 g  

<u>27984.1311 g  of calcium oxide will be produced.</u>

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How do chemists express the rates of chemical reactions
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They expressed it as rate of change in concentration of reactants or products in a chemical reaction

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Not A because

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