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andrezito [222]
3 years ago
13

Consider the formation of nitrogen dioxide and oxygen: NO(g)+O3(g)⇌NO2(g)+O2(g) The reaction is first order in O3 and second ord

er overall. What is the rate law? (A) rate=k[NO]2[O3]2(B) rate=k[NO][O3]2(C) rate=k[O3](D) rate=k[NO](E) rate=k[NO][O3](G) rate=k[NO]2[O3]
Chemistry
1 answer:
Leno4ka [110]3 years ago
3 0

Answer:

The rate law is rate = k[NO][O₃]

Option E) is the right answer.

Explanation:

Hi there!

For this generic reaction:

A + B → products

the rate law will be:

rate = k[A]ⁿ[B]ᵃ

this reaction is n-order in A and a-order in B. The overall reaction is the sum of the orders of each reactant, in this case:

Overall order of the reaction = n + a

In our problem, we know that the reaction is first order in O₃ and second order overall. Then:

Overall order of the reaction = Order in NO + Order in O₃

2 = n + 1

2 - 1 = n

n = 1

Then, the reaction is first order in NO and first order in O₃.

The rate law will be:

rate = k[NO][O₃]

The right answer is the option E).

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Read 2 more answers
What is the reaction quotient, Q, for this system when [N2] = 2.00 M, [H2] = 2.00 M, and [NH3] = 1.00 M at 472°C?
cupoosta [38]

Answer : The value of reaction quotient, Q is 0.0625.

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Concentration of N_2 = 2.00 M

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Concentration of NH_3 = 1.00 M

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The balanced equilibrium reaction is,

N_2+3H_2\rightleftharpoons 2NH_3

The expression of reaction quotient for this reaction is,

Q=\frac{[Product]^p}{[Reactant]^r}\\Q=\frac{[NH_3]^2}{[N_2]^1[H_2]^3}

Now put all the given values in this expression, we get

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4 years ago
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