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1 year ago

What is the approxamation of the square root of 110

Mathematics

2 answers:

hammer [34]1 year ago

8 0

Answer:

10.49

Step-by-step explanation:

the first number after the point is not higher than five so it would not be changed but the second number after the point is 8 so u can choose to change it to one or two decimal points according to the question. Note if it's two u choose then the answer will be 10. 50.

FrozenT [24]1 year ago

4 0

Answer: 10.488 Promise

Step-by-step explanation:

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Evaluate the expression if a =2.4, b = 0.237, and c =9.49

IRISSAK [1]

Answer:

(0.237)

Step-by-step explanation:

7 0

4 years ago

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Write a cubic function whose graph goes through the points: (-5, 0) (1, 0) (2, -2) (4, 0)

Free_Kalibri [48]

Answer:

f(x) = $\frac{1}{7}(x+5)(x-1)(x-4)$

Step-by-step explanation:

Let the equation of the give cubic function is,

f(x) = p(x - a)(x - b)(x - c)

Here, a, b, c and d are the x-intercepts of the given graph.

Since, x-intercepts given in the graph are x = -5, 1 and 4,

Equation of the curve will be,

f(x) = p(x + 5)(x - 1)(x - 4)

Since, the graph of this function passes through (2, -2) also

-2 = p(2 + 5)(2 - 1)(2 - 4)

-2 = -p(14)

p = $\frac{2}{14}$

p = $\frac{1}{7}$

Therefore, equation will be,

f(x) = $\frac{1}{7}(x+5)(x-1)(x-4)$

5 0

3 years ago

Please help!! i need help asap <33

7nadin3 [17]

Answer:

Step-by-step explanation:

5 0

3 years ago

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Melody paid off a loan of $120,000 in 10 years. If she made a payment of $1,225 each month, then what was the simple interest ra

sdas [7]

I think it’s .01% because 1225/120000=.010208

7 0

3 years ago

Plz help me!!!!!!!!!

Over [174]

Answer: $\bold{\dfrac{4\pm \sqrt{6}}{2}}$

<u>Step-by-step explanation:</u>

$\dfrac{3}{y-2}-2=\dfrac{1}{y-1}\\\\\\\text{Multiply by the LCD (y-2)(y-1) to clear the denominator:}\\\\\dfrac{3}{y-2}(y-2)(y-1)-2(y-2)(y-1)=\dfrac{1}{y-1}(y-2)(y-1)\\\\\\3(y-1)-2(y-2)(y-1)=1(y-2)\\\\3y-3-2(y^2-3y+2)=y-2\\\\3y-3-2y^2+6y-4=y-2\\\\-2y^2+9y-7=y-2\\\\0=2y^2-8y+5\quad \rightarrow \quad a=2,\ b=-8,\ c=5\\\\\\\text{Quadratic formula is: }x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(-8)\pm \sqrt{(-8)^2-4(2)(5)}}{2(2)}\\\\\\.\ =\dfrac{8\pm \sqrt{64-40}}{2(2)}$

$.\ =\dfrac{8\pm \sqrt{24}}{2(2)}\\\\\\.\ =\dfrac{8\pm 2\sqrt{6}}{2(2)}\\\\\\.\ =\dfrac{4\pm \sqrt{6}}{2}$

7 0

3 years ago