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schepotkina [342]
3 years ago
12

Find the equation of the line that passes through the point left (-9,12) and is perpendicular to the line y=3/2x-1/2. Write the

equation using the​ slope-intercept form.
Mathematics
1 answer:
ohaa [14]3 years ago
8 0

Answer:

The answer to your question is: y = -2/3 x + 18

Step-by-step explanation:

Data

Point = (-9, 12)

line   y = 3/2x -1/2     perpendicular

Process

The line must be perpendicular to the line given. Then,

slope is the line given = 3/2, we change it because the lines must be perpendicular ,

New slope         M =  -2/3

New line       y-y1 = m(x - x1)

                     y - 12 = -2/3 (x + 9)             Substitution

                   3( y - 12) = -2(x + 9)

                   3y - 36 = -2x - 18                 Simplify

                   3y = -2x - 18 + 36

                   3y = -2x + 18

                      y = -2/3 x+ 18                      Result

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Serhud [2]

Answer:

He paid $253.09 in interest.

Step-by-step explanation:

To find how much did he pay in interest, we use the simple intrest formula, that is given by:

I = Prt

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In our problem, we have that:

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At 4.75% yearly. We measure the time in days, so we have to divide this value by 365. So r = \frac{0.0475}{365}.

From December 26, 2019 to February 21, 2021, there are 422 days, so t = 422.

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I = 4,400\frac{0.0475}{365} 422

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Answer:

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