Answer:
438,012 ways.
Step-by-step explanation:
We have been given that each coupon code will have three letters followed by two digits. The letters M, N, and O and the digits 1, 3, 5, and 7 will not be used. So, there are 23 letters and 6 digits that will be used.
Since the letters and digits can be repeated, so we will use fundamental principal of counting.
For first place, we can use 23 letters, for 2nd and 3rd place we can use 23 letters.
We can use 6 digits for 1st digit place and 6 digit for 2nd digit place as repetition is allowed.
So we can choose coupon code is following ways:
Therefore, we can choose coupon codes in 438,012 ways.
The answer is b. would u like to see steps or are you good?
Answer:
Step-by-step explanation:
First use distributive property: a(b + c) = a*b + a*c
3n - 6 = -8(6 + 5n)
3n - 6 = 6 * (-8) + 5n *(-8)
3n - 6 = -48 - 40n
Now add 40n to both sides
3n - 6 + 40n = -48 - 40n + 40n
43n - 6 = -48
Now add 6 to both sides
43n - 6 + 6 = -48 + 6
43n = -42
n = -42 /43
<span>Two dice (each die has 6 sides) can be combined to form 36 different possibilities (6 x 6).
</span>
x=45
Step-by-step explanation:
x/5+7-7=16-7
5/1×x/5=9×5/1
x=45