10 22 - 2 2 B. 4 D mZADB= m2BDC
1 answer:
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Answer:
No
Reasoning:
If something is a perfect cube, it is able to be put under a cube root () and will result in an integer (a non-decimal number > 0, basically).
So let's calculate , and see if the result is an integer.
= 3.634.......
As you can see, the result is not an integer, therefore 48 is not a perfect cube.