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Ira Lisetskai [31]
4 years ago
14

PLEASE HELP! Find the point slope form and slope intercept form, indicate the slope and y-int?

Mathematics
1 answer:
Ksju [112]4 years ago
7 0

Answer:no

hccer

Step-by-step explanation:

my name is william schruge

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The amounts a soft drink machine is designed to dispense for each drink are normally distributed, with a mean of 12.1 fluid ounc
yaroslaw [1]

Complete Question

The amounts a soft drink machine is designed to dispense for each drink are normally distributed, with a mean of 12.1 fluid ounces and a standard deviation of 0.3 fluid ounce. A drink is randomly selected.

Required:

a) Find the probability that the drink is less than 11.9 fluid ounces

b) Find the probability that the drink is between 11.6 and 11.9 fluid ounces

c) Find the probability that the drink is more than 12.6 fluid ounces. Can this be considered an unusual​ event? Explain your reasoning.

Answer:

a

  P(X < 11.9 ) =  0.25239  [/tex ]   b   [tex]P(  11.6 < X < 11.9 ) =  0.20463

c

  P(X > 12.6 ) =  0.047757  [/tex ]   Yes  It is an unusual event Step-by-step explanation:From the question we are told that     The mean is  [tex]\mu =  12.1

   The standard deviation is  \sigma  =0.3

Generally the probability that the drink is less than 11.9 fluid ounces is mathematically represented as

      P(X < 11.9 ) =  P(\frac{X -\mu}{\sigma } < \frac{11.9 - 12.1}{0.3} )

   \frac{X -\mu}{\sigma }  =  Z (The  \ standardized \  value\  of  \ X )

      P(X < 11.9 ) =  P(Z< -0.667 )&#10;[/tex ]From the z table  the area under the normal curve to the left corresponding to -0.667  is  P(Z< -0.667 ) = 0.25239So  [tex] P(X < 11.9 ) =  0.25239  [/tex ]    Generally the  probability that the drink is between 11.6 and 11.9 fluid ounces is mathematically represented as [tex] P(  11.6 < X < 11.9 ) =  P(  \frac{11.6 -12.1}{0.3} < \frac{X -\mu}{\sigma } < \frac{11.9 - 12.1}{0.3} )&#10;

   P(  11.6 < X < 11.9 ) =  P( -1.667 < Z < -0.667 )&#10;

=> P(  11.6 < X < 11.9 ) =  P( Z < -0.667) -  P ( Z < -1.667 )&#10;

From the z table  the area under the normal curve to the left corresponding to  -1.667  is

  P(Z< -1.667 ) = 0.047757

So

       P(  11.6 < X < 11.9 ) =  0.25239  - 0.047757

=>      P(  11.6 < X < 11.9 ) =  0.20463

Generally the probability that the drink is more than 12.6 fluid ounces is mathematically represented as

         P(X > 12.6 ) =  P(\frac{X -\mu}{\sigma } > \frac{12.6 - 12.1}{0.3} )

      [tex] P(X >12.6 ) =  P(Z> 1.667 ) [/tex ]

From the z table  the area under the normal curve to the right corresponding to 1.667  is

P(Z> 1.667 ) = 0.047757

So

[tex] P(X > 12.6 ) =  0.047757  [/tex ]        

Given that this probability is less than 0.05 , it mean it is an unusual​ event

3 0
3 years ago
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