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Alla [95]
4 years ago
6

Which table can be created using the equation below? –2 + 4x = y A 2-column table with 3 rows. Column 1 is labeled x with entrie

s negative 5, 0, 3. Column 2 is labeled y with entries negative 22, negative 2, 10. A 2-column table with 3 rows. Column 1 is labeled x with entries negative 22, negative 2, 10. Column 2 is labeled y with entries negative 5, 0, 3. A 2-column table with 3 rows. Column 1 is labeled x with entries negative 5, 0, 3. Column 2 is labeled y with entries negative 18, negative 2, 10. A 2-column table with 3 rows. Column 1 is labeled x with entries negative 18, negative 2, 10. Column 2 is labeled y with entries negative 5, 0, 3.
Mathematics
2 answers:
inessss [21]4 years ago
7 0

Answer:

it is c

Step-by-step explanation:

Pachacha [2.7K]4 years ago
5 0

The correct answer is C. A 2-column table with 3 rows. Column 1 is labeled x with entries negative 5, 0, 3. Column 2 is labeled y with entries negative 18, negative 2, 10.

Explanation:

The purpose of an equation is to show the equivalence between two mathematical expressions. This implies in the equation "–2 + 4x = y" the value of y should always be the same that -2 + 4x. Additionally, if a table is created with different values of x and y the equivalence should always be true. This occurs only in the third option.

   x                 y

   5                -18    

   0                -2

   3                 10

First row:

-2 + 4 (5) = y  (5 is the value of x which is first multyply by 4)

-2 + 20 = -18 (value of y in the table)

Second row:

-2 + 4 (0) y

-2 + 0 = -2

Third row:

-2 + 4 (3) = y

-2 + 12 = 10

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Answer:

The point-slope form of the equation of the perpendicular line that goes through (5, 0) is:

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Step-by-step explanation:

Given the equation

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comparing the equation with the slope-intercept form

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Here,

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so the slope of the line is 2.

As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line, so

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Therefore, the point-slope form of the equation of the perpendicular line that goes through (5, 0) is:

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y-0=\frac{-1}{2}\left(x-5\right)

y=\frac{-1}{2}\left(x-5\right)

\:y=-\frac{1}{2}x+5\cdot \:\frac{1}{2}

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