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gtnhenbr [62]
1 year ago
12

help me!!! Write an equation of the line passing through the point (2, 8) that is perpendicular to the line 2x - 3y = 7

Mathematics
1 answer:
galben [10]1 year ago
5 0

Answer:

y = -3/2x +11

Step-by-step explanation:

First you have to change the equation from standard form to slope form.

y = mx + b

2x-3y=7 --> subtract 2x from both sides

-3y = -2x + 7 --> now divide both sides by -3 to get y by itself

y = 2/3x - 7/3  --> the reason 2/3x is positive is because when there are two negatives it turns to a positive.

now you have to use point slope form y - y1 = m (x - x1)

x1 and y1 would be your point. 2 is x1 and 8 is y1

y - 8 = -3/2 (x - 2) --> the reason that m is -3/2 is because a perpendicular equation is the opposite reciprocal of the original slope

next distribute the -3/2

y-8 = -3/2x + 3 --> and now add 8 to 3 to get why by it self

now you have y = -3/2x + 11

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An article describes an experiment to determine the effectiveness of mushroom compost in removing petroleum contaminants from so
alexgriva [62]

Solution :

Let p_1 and p_2  represents the proportions of the seeds which germinate among the seeds planted in the soil containing 3\% and 5\% mushroom compost by weight respectively.

To test the null hypothesis H_0: p_1=p_2 against the alternate hypothesis  H_1:p_1 \neq p_2 .

Let \hat p_1, \hat p_2 denotes the respective sample proportions and the n_1, n_2 represents the sample size respectively.

$\hat p_1 = \frac{74}{155} = 0.477419

n_1=155

$p_2=\frac{86}{155}=0.554839

n_2=155

The test statistic can be written as :

$z=\frac{(\hat p_1 - \hat p_2)}{\sqrt{\frac{\hat p_1 \times (1-\hat p_1)}{n_1}} + \frac{\hat p_2 \times (1-\hat p_2)}{n_2}}}

which under H_0  follows the standard normal distribution.

We reject H_0 at 0.05 level of significance, if the P-value or if |z_{obs}|>Z_{0.025}

Now, the value of the test statistics = -1.368928

The critical value = \pm 1.959964

P-value = $P(|z|> z_{obs})= 2 \times P(z< -1.367928)$

                                     $=2 \times 0.085667$

                                     = 0.171335

Since the p-value > 0.05 and $|z_{obs}| \ngtr z_{critical} = 1.959964$, so we fail to reject H_0 at 0.05 level of significance.

Hence we conclude that the two population proportion are not significantly different.

Conclusion :

There is not sufficient evidence to conclude that the \text{proportion} of the seeds that \text{germinate differs} with the percent of the \text{mushroom compost} in the soil.

8 0
3 years ago
I need some help please​
Mama L [17]

Answer:

109

Step-by-step explanation:

Formula

<ZHG + <IHZ = <IHG

Givens

<ZHF = 11x - 1

<IHZ = 24

<IHG = 12x + 13

Solution

11x - 1 + 24 = 12x + 13             Combine terms on the left

11x + 23 = 12x + 13                  Subtract 13 from both sides

<u>      - 13             - 13  </u>

11x + 10 = 12x                           Subtract 11x from both sides

<u>-11x           -11x</u>

        10 =   x

Answer

11x - 1 = 11*10 - 1 = 110 - 1 = 109

7 0
2 years ago
HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP
tankabanditka [31]

Answer:

join the meet /vwd-cfbx-dtk

7 0
3 years ago
Read 2 more answers
there are 4 planets. the first planet has an orbit of 3 years. The second planet has an orbit of 5 years. The third planet has a
Margarita [4]

Find the LCM of the four numbers (3, 5, 8, 12)

3: 3

5: 5

8: 2 * 2 * 2

12: 2 * 2 * 3

LCM = 2 * 2 * 2 * 3 * 5

        = 120

Answer: 120 years


6 0
3 years ago
Listed are the quantities of green grapes Martha bought for four months in the amount that she spent on them. In May, she bought
Firlakuza [10]

Answer:

It is in February that the unit price of grapes ($2.70 per pound of grapes) is the same as that of May.

Step-by-step explanation:

Complete Question

Select the correct month.

Listed are the quantities of green grapes Martha bought for four months and the amount that she spent on them. In May, she bought 2 pounds of grapes for $5.40, in which month was the unit price the same as it was in May?

January

2 pounds for $7.40

February

4 pounds for $10.80

March

5 pounds for $11.65

April

3 pounds for $7.50

Solution

In May, Martha bought 2 pounds of grapes for $5.40.

The unit price per pound = (5.40/2) = $2.70 per pound of grapes.

We can then do this for the months given to obtain which month in which the unit price is the same as it was in May?

For January

She bought 2 pounds of grapes for $7.40

Unit price per pound = (7.40/2) = $3.70 per pound of grapes.

For February

Martha bought 4 pounds of grapes for $10.80.

Unit price per pound = (10.80/4) = $2.70 per pound of grapes.

March

She bought 5 pounds of grapes for $11.65.

Unit price per pound = (11.65/5) = $2.33 per pound of grapes.

April

She bought 3 pounds of grapes for $7.50.

Unit price per pound = (7.50/3) = $2.50 per pound of grapes.

It is evident that it is in February that the unit price of grapes ($2.70 per pound of grapes) is the same as that of May.

Hope this Helps!!!

7 0
3 years ago
Read 2 more answers
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