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SSSSS [86.1K]
3 years ago
14

Petro was given this system of equations. Negative 14 x minus 2 y = 24. 14 x + 8 y = negative 12. Petro’s work is shown in the t

able. Where, if anywhere, did Petro first make a mistake? Steps Petro’s Work Step 1 Negative 14 x minus 2 y = 24. 14 x + 8 y = negative 12. 6 y = 12. Step 2 6 y = 12. y = 2. Step 3 Negative 14 (2) minus 2 y = 24. Negative 28 minus 2 y = 24. Negative 2 y = 52. y = negative 26.
step 1
step 2
step 3
no mistake
Mathematics
2 answers:
prisoha [69]3 years ago
6 0

Answer:

C: Step 3 is where the mistake was made

Step-by-step explanation:

bogdanovich [222]3 years ago
3 0

Answer:

C Step 3

Step-by-step explanation:

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Mr. Burns has 500 pieces of candy and he wanted
Genrish500 [490]

Answer:

3

Step-by-step explanation:

500 - 10 = 490

long way:

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4 years ago
Evaluate the determinant of the matrix.<br> -4 5 6<br> 0 4 4<br> -2 -5 4<br> I need the work plz
FromTheMoon [43]

Answer:

-136

Step-by-step explanation:

We have to find the determinant of the following matrix:

\left[\begin{array}{ccc}-4&5&6\\0&4&4\\-2&-5&4\end{array}\right]

We can find the determinant by expanding via 1st column. i.e. by taking each element of 1st column and multiplying it by its co-factor matrix as shown below:

det \left[\begin{array}{ccc}-4&5&6\\0&4&4\\-2&-5&4\end{array}\right]

= (-4 \times det \left[\begin{array}{cc}4&4\\-5&4\end{array}\right]) - (0 \times (-4 \times det \left[\begin{array}{cc}5&6\\-5&4\end{array}\right]))+ ((-2) \times det\left[\begin{array}{cc}5&6\\4&4\end{array}\right])\\\\ =-4 \times (16 + 20)-(0)+(-2 \times 20-24)\\\\ =-4(36)+(-2(-4))\\\\ =-144+8\\\\ =-136

The notation det() stands for determinant of the matrix.

Therefore, the determinant of the given matrix is -136

8 0
3 years ago
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Amiraneli [1.4K]

Answer:

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Step-by-step explanation:

The double negative automatically makes something positive. Your new expression is 5x^4 + 6x^4.

The only other thing you need to do is combine like terms by adding them together.

11x^4

3 0
3 years ago
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