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3 years ago

Help Fast Quicklkkkkkkkkkk

Mathematics

2 answers:

Rainbow [258]3 years ago

5 0

Answer:

Now from the top make it drop that a wapgbrbehdhdjfh I D fgddhhdhsddhhhdhdhhddddd

77julia77 [94]3 years ago

3 0

I can’t see the graph so well

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If the measure of an interior angle is 45°, what is the measure of the exterior angle?

masha68 [24]

It would be 135°

There is 180° in a triangle, so you subtract 180°-45°

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4 years ago

Plz answer. only if correct

earnstyle [38]

Answer:10001.5%+10303990=f(g+2)

Step-by-step explanation:

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3 years ago

I need the answer to the problem

Leya [2.2K]

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3 years ago

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A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot

ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = $(x\times x)$

$=x^2$

The volume of the box is = area of the base × height

$=x^2h$

Therefore,

$x^2h=272$

$\Rightarrow h=\frac{272}{x^2}$

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

$=20x^2$ cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

$=10x^2$ cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

$=4xh\times 1.5$ cents

$=6xh$ cents

Total cost = $(20x^2+10x^2+6xh)$

$=30x^2+6xh$

Let

C $=30x^2+6xh$

Putting the value of h

$C=30x^2+6x\times \frac{272}{x^2}$

$\Rightarrow C=30x^2+\frac{1632}{x}$

Differentiating with respect to x

$C'=60x-\frac{1632}{x^2}$

Again differentiating with respect to x

$C''=60+\frac{3264}{x^3}$

Now set C'=0

$60x-\frac{1632}{x^2}=0$

$\Rightarrow 60x=\frac{1632}{x^2}$

$\Rightarrow x^3=\frac{1632}{60}$

$\Rightarrow x\approx 3$

Now $C''|_{x=3}=60+\frac{3264}{3^3}>0$

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is $=\frac{272}{3^2}$

=30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0

3 years ago

On a trolley ride around an amusement park, a child traveled from one signpost to a second signpost at a constant speed of 125 m

Feliz [49]

Answer:

If a child took just one minute, distance is less than 0,8 km

Step-by-step explanation:

speed= 125 m/min = 0,125 km/min,

distance=0,8 km

time= 0,8 km / 0,125 km/min = 6,4 min.

5 0

4 years ago