3 years ago

Help Fast Quicklkkkkkkkkkk

Mathematics

2 answers:

Rainbow [258]3 years ago

5 0

Answer:

Now from the top make it drop that a wapgbrbehdhdjfh I D fgddhhdhsddhhhdhdhhddddd

77julia77 [94]3 years ago

3 0

I can’t see the graph so well

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$\bf \cfrac{d}{dx}[u(x)\cdot v(x)]\implies \cfrac{du}{dx}\cdot v(x)+u(x)\cdot \cfrac{dv}{dx}\quad 
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\\\\
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\end{cases}
\\\\
\left[ \cfrac{du}{dx} \right]_{x=0}\cdot v(0)+u(0)\cdot \left[ \cfrac{dv}{dx} \right]_{x=0}$

so.. hmm pretty sure you know what that is

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Murrr4er [49]

Answer:

Step-by-step explanation:

Hello, please consider the following.

$x^2+x-42\\\\\text{The sum of the zeroes is -1=-7+6 and the product is -42=-7*6.}\\\\\text{So, we can factorise.}\\\\x^2+x-42\\\\=x^2+7x-6x-42\\\\=x(x+7)-6(x+7)\\\\=(x+7)(x-6)$