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LenKa [72]
1 year ago
10

Use prime factorization to find the LCM of each set of numbers:A) 15,21B)15,30C)24,72D)16,42E)8, 30F)18,30G) 8,16,20

Mathematics
1 answer:
jarptica [38.1K]1 year ago
4 0

Solution

For this case we can do the following:

A) 15, 21

LCM= 105

15= 3*5

21 = 7*3

LCM= 3*5*7

b) 15,30

LCM= 30

15= 3*5

30 = 2*5

LCM= 2*3*5= 30

c) 24,72

LCM= 72

24= 2*3*4

72= 2* 2*2*3*3

LCM= 2*2*2*3*3

d) 16,42

LCM= 336

16= 2*2*4

42= 2*3*7

LCM= 2*2*3*7*4

e) 8,30

LCM=120

8= 2*4

30= 2*3*5

LCM= 2*3*4*5=120

f) 18,30

LCM=90

18= 2*3*3

90= 2*5*3*3

LCM= 2*5*3*3

g) 8,16,20

LCM= 80

8= 2*2*2

16= 2*2*2*2

20= 2*2*5

LCM= 2*2*2*2*5

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laiz [17]

Answer:

The standard form of such an equation is Ax + By + C = 0 or Ax + By = C. When you rearrange this equation to get y by itself on the left side, it takes the form y = mx +b. This is called slope intercept form because m is equal to the slope of the line, and b is the value of y when x = 0, which makes it the y-intercept.

Step-by-step explanation:

8 0
3 years ago
If you can help with any of these two or both that would be great ! :) <br> thanks
Vladimir [108]

Answer:

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Step-by-step explanation:

try mulitply the numbers

7 0
3 years ago
Simplify these expressions. a.2r+3+4r. b.8+3d+d. c.mn+ (-3mm)+6 d. 10s + (-10) + (-4s)
Maru [420]

Step-by-step explanation:

<em>Combine like terms</em>

a. 2r + 3 + 4r = (2r + 4r) + 3 = 6r + 3

b. 8 + 3d + d = (3d + d) + 8 = 4d + 8

c. mn + (-3mn) + 6 = (mn - 3mn) + 6 = -2mn + 6

d. 10s + (-10) + (-4s) = (10s - 4s) - 10 = 14s - 10

<em>Terms are called "like terms" if they have the same variable part (the same letters in the same powers). Like terms differ at most coefficient.</em>

7 0
4 years ago
Suppose a parabola has vertex (6,5) and also passes through the point (7,7). Write the equation of the parabola in vertex form.
jek_recluse [69]

Answer:

Choice B: y = 2\, (x - 6)^{2} + 5.

Step-by-step explanation:

For a parabola with vertex (h,\, k), the vertex form equation of that parabola in would be:

\text{$y = a\, (x - h)^{2} + k$ for some constant $a$}.

In this question, the vertex is (6,\, 5), such that h = 6 and k = 5. There would exist a constant a such that the equation of this parabola would be:

y = a\, (x - 6)^{2} + 5.

The next step is to find the value of the constant a.

Given that this parabola includes the point (7,\, 7), x = 7 and y = 7 would need to satisfy the equation of this parabola, y = a\, (x - 6)^{2} + 5.

Substitute these two values into the equation for this parabola:

7 = (7 - 6)^{2}\, a + 5.

Solve this equation for a:

7 = a + 5.

a = 2.

Hence, the equation of this parabola would be:

y = 2\, (x - 6)^{2} + 5.

4 0
3 years ago
Two numbers that differ by 46
Reil [10]

the complete question is

Find two numbers whose difference is 46 and whose product is a minimum


Let

x------->larger number

y-------> smaller number

P-------> product of the two numbers


we know that

x-y=46\\ y=x-46-----> equation 1

P=x*y-----> equation 2


substitute equation 1 in equation 2

P=x*[x-46]\\ P=x^{2} -46x


using a graph tool

see the attached figure


Find the value of x for that the product P is a minimum

the vertex is the point (23,-529)

that means, for x=23

the product is a minimum P=-529


find the value of y

y=x-46\\ y=23-46\\ y=-23


therefore


the answer is

the numbers are 23 and -23

7 0
3 years ago
Read 2 more answers
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