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4 years ago

Question number 7 Give a reasonable domain and range for the function in this context

Mathematics

1 answer:

alina1380 [7]4 years ago

3 0

Answer: D: [0, ∞)

R: [0, ∞)

Step-by-step explanation:

f(x) = 1.5x

x is the number of bottles

f(x) is the cost

Domain is the x-values. The least amount of bottles you can buy is 0 and the most you can buy is infinite <em>(technically you can only buy the amount you can afford and the amount the store has to sell but for mathematical purposes you can buy an infinite amount)</em>

So, the domain (D) is x = 0 to ∞ → D: [0, ∞)

Range is the y-values. The least and most amounts are based on the domain. Since the smallest x-value is 0, input that value into the equation to solve for f(x). Similarly, input the greatest x-value to solve for f(x).

f(x) = 1.5(0)

= 0

f(x) = 1.5(∞)

= ∞

So, the range (R) is f(x) = 0 to ∞ → R: [0, ∞)

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Construct a 95% prediction interval for y given x=-3.5, ^y= 2.097x - .552 and se= .976

Rasek [7]

Answer:

95% Confidence interval for y

= (-9.804, -5.979)

Lower limit = -9.804

Upper limit = -5.979

Step-by-step explanation:

^y= 2.097x - 0.552

x = -3.5

Standard error = 0.976

Mathematically,

Confidence Interval = (Mean) ± (Margin of error)

Mean = 2.097x - 0.552 = (2.097×-3.5) - 0.552 = - 7.8915

(note that x=-3.5)

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error of the mean)

Critical value for 95% confidence interval = 1.960

Standard Error of the mean = 0.976

95% Confidence Interval = (Mean) ± [(Critical value) × (standard Error of the mean)]

CI = -7.8915 ± (1.960 × 0.976)

CI = -7.8915 ± 1.91296

95% CI = (-9.80446, -5.97854)

95% Confidence interval for y

= (-9.804, -5.979)

Hope this Helps!!!

3 0

3 years ago

Can you help me please?

joja [24]

Answer:

y=x^2

Step-by-step explanation:

if you look at it, x is constantly multiplying itself so-

6 0

3 years ago

Evaluate the expression "12 - (-36) / -6"

Allisa [31]

Answer:

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3 0

3 years ago

Find the area of the region between two concentric circular paths. If the radii of the circular paths are 210 m. and 490 m. resp

taurus [48]

Given :

The radii of the circular paths are 210 m. and 490 m.

To Find :

The area of the region between two concentric circular paths.

Solution :

Area of the outer circle :

$\: \qquad \dashrightarrow \sf{{ \pi \: \times {(490)}^{2} {m}^{2}}}$

$\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{7} \times \:490 \times 490 \: {m}^{2}}}$

$\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{ \cancel{7}} \times \cancel{490} \times 490 \: {m}^{2}}}$

$\: \qquad \dashrightarrow \sf{{ \ {22} \times 70 \times 490 \: {m}^{2}}}$

$\: \qquad \dashrightarrow \bf{{ \ 754600 \: {m}^{2}}}$

⠀

Area of the inner circle :

$\: \qquad \dashrightarrow \sf{{ \pi \: \times {(210)}^{2} {m}^{2}}}$

$\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{7} \times \:210 \times 210 \: {m}^{2}}}$

$\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{ \cancel{7}} \times \cancel{210} \times 210 \: {m}^{2}}}$

$\: \qquad \dashrightarrow \sf{{ \ {22} \times 30 \times 210 \: {m}^{2}}}$

$\: \qquad \dashrightarrow \bf{{ \ 138600 \: {m}^{2}}}$

⠀

Therefore,

Area of the region inside the circular paths :

$\: \qquad \dashrightarrow \sf{{ \ (754600 - 138600 ) \: {m}^{2}}}$

$\: \qquad \dashrightarrow \bf{{ \ 616000 \: {m}^{2}}}$

6 0

3 years ago

PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!!

fomenos

Answer:

Step-by-step explanation:

3 0

3 years ago