Good evening ,
Answer:
x = StartFraction negative 8 Over 3 EndFraction, –2
Step-by-step explanation:
3x² + 14x + 16 = 0
3x² + 6x + 8x + 16 = 0
(3x² + 6x) + (8x + 16) = 0
3x(x+2) + 8(x+2) = 0
(x+2)(3x+8) = 0
x = -2 , x = -8/3.
:)
Answer:
Step-by-step explanation:
Answer:
x = 28
Step-by-step explanation:
Given that lines AB and CD are straight lines that intersects at O, it follows that the pair of opposite vertical angles formed are congruent.
Thus,
<AOD = <BOC
<AOD = 152°
<BOC = 3x + x + (x + 12) (angle addition postulate)
<BOC = 5x + 12
Since <AOD = <BOC, therefore,
152° = 5x + 12 (substitution)
152 - 12 = 5x (subtraction property of equality)
140 = 5x
140/5 = x (division property of equality)
28 = x
x = 28
It is true because
when you separate 2y^2 +9y -18, you are supposed to get the factors
(2y-3)(y+6), when you multiply this it gives you the first equation, we know
this because when we multiply the first term it gives us exactly 2y^2 and if we
multiply the last ones it gives you -18, now here is the tricky part, when we
multiply the middle part we get 12y and -3y, when we add these up we get 9y,
now is that the same middle as in the equation? Yes… then our factors are correct
making this true
Hope this helps
