Answer:
The answer is B = 365
Explanation:
The following variable were initialized:
a = 1
b = 10
c = 100
x = 0
Then we store the value of 'c' times 3 in 'x'
x = 3 * c = 3 * 100 = 300
x = 300
Then we add the value of 'b' times 6 to the value already in 'x'
x = x + 'b' times 6
x = x + (b * 6) = 300 + (10 * 6) = 300 + 60 = 360
x = 360
Then we add the value of 'a' times 5 to the value already in 'x'
x = x + 'a' times 5
x = x + (a * 5) = 360 + (1 * 5) = 360 + 5 = 365
x = 365.
Therefore, the value of 'x' displayed is 365.
Answer:
Explanation:
The following Python program uses a combination of dictionary, list, regex, and loops to accomplish what was requested. The function takes a file name as input, reads the file, and saves the individual words in a list. Then it loops through the list, adding each word into a dictionary with the number of times it appears. If the word is already in the dictionary it adds 1 to its count value. The program was tested with a file named great_expectations.txt and the output can be seen below.
import re
def wordCount(fileName):
file = open(fileName, 'r')
wordList = file.read().lower()
wordList = re.split('\s', wordList)
wordDict = {}
for word in wordList:
if word in wordDict:
wordDict[word] = wordDict.get(word) + 1
else:
wordDict[word] = 1
print(wordDict)
wordCount('great_expectations.txt')
Answer: Option C is correct
Explanation:
Option C is correct
Through the use of <span>satellite imagery</span>