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Leno4ka [110]
3 years ago
14

Which wireless communication is typically limited to six feet of distance?

Computers and Technology
1 answer:
Tcecarenko [31]3 years ago
4 0

Answer:

Bluetooth is a wireless communication    is  typically limited to   six feet distances

Explanation:

Bluetooth is one type of communication maximum it covers  10 meters to 30 meters.   but it is one to one communication made for data transactions.  After  25 meters of coverage on communication will be very slow on data transactions. But Bluetooth has also had a limitation.

IR.  It is one of communication where infrared technology used. It is like face to face communication and speed of data transaction limited and it is also one to one communication made for data transactions. Communication paired and covered very little distances.

NFC it is chip-based and covers very little in fact just to device meet each and communication started. And very it caries very little data during the data transactions. it is also one to one communication made for data transactions

RFID is one of communication and it is powerful to cover more areas with multiple connections at the same time. It has a limitation  in distance and it covers  like a net with a specific distance  

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Write a program. Commence the change to be dispensed from a vending machine. An item machine can cost between $0.25 send a dolla
SSSSS [86.1K]

Answer:

Explanation:

The objective of this question is to write a java program for a vending machine.

/* This program finds out what amount the vending machine is going to dispense. A given item in the machine can cost between $0.25 and a dollar in five-cent increments (25, 30, 35, 40...90, 95 or 100), and the machine accepts only a dollar bill to pay for the item. */

// Compile: javac PP10. java

// Run: java PP10

// imported the scanner class from util package.

import java. util. Scanner;

//class declaration

public class PP10 {

// main method is defined here.

       public static void main(String[]   args)

          {

// declaration of the variables.

             Scanner keyboard=new Scanner (System.in):

//taking the string type input

              int nl, amount, n2, n3, n4, n5;

            System.out.println("Enter price of item (from 20

cents to a dollar, in 5-cents) :");

             n1=keyboard. nextInt ();

            System.out.println("You bought an item for "+n1+"

cents and gave me a dollar");

            System.out.println ("so your change is ");

//the amount is first calculated.

          amount=100-n1;

// quarter value is calculated

            n2=amount/25;

// rest amount is get here.

            amount=amount%25;

// dime value is calculated

             n3-amount/10;

// rest amount is calculated

            amount=amount%10;

// value of nickel is calculated here

            n4=amount/5;

// rest amount is calculated

            amount=amount%5;

//at last the number of pennies is get

            n5=amount;

// Display output

              System. out . println(n2+" quarters") :

              System. out . println(n3+" dimes") ;

              System. out . println(n4+" nickels") ;

              System. out . println(n5+" pennies") ;

       }

  }

Output:

Enter the price of the item (from 20 cents to a dollar, in 5 - cents):

So, you bought an item for $0.45 and gave me one dollar; thus, your change is

2 quarters

0 dimes

1 nickel

0 pennies

4 0
3 years ago
Write a method called removeHighPrice that will go through a provided ArrayList called prices and removes the first price that i
Diano4ka-milaya [45]

Answer:

The method written in Java is as follows:

public static ArrayList<Double> removeHighPrice (ArrayList<Double> prices){

       for(int i =0;i<prices.size();i++){

     if(prices.get(i) > 5.00){

         prices.remove(i);  

         break;

     }

 }

 return(prices);  

 }

Explanation:

This line declares the method

public static ArrayList<Double> removeHighPrice (ArrayList<Double> prices){

This line iterates through the ArrayList named prices

       for(int i =0;i<prices.size();i++){

This checks if current price is greater than 5

     if(prices.get(i) > 5.00){

If yes, the price is removed

         prices.remove(i);  

And the loop is terminated

         break;

     }

 }

This returns the ArrayList

 return(prices);  

 }

<em>I've added as an attachment, the complete program which includes the main method</em>

Download txt
6 0
3 years ago
In Java, it is possible to create an infinite loop out of while and do loops, but not for-loops. true or false
soldier1979 [14.2K]

Answer:

False is the correct answer for the above question.

Explanation:

  • In java programming language or any other programming language, any loop can be infinite.
  • It is because the infinite loop is called for that loop which is not run in a finite number of times.
  • The loop is used to repeat some lines in a finite number of times. Any loop has three things- first is the initial value which tells the loop to start, The second is the condition check which states when the loop will stop and the third is an operation which directs some variable, so that the condition may be false after some finite amount of time.
  • If the condition will not false in any iteration of the loop, then the loop can proceed for an infinite amount of time.
  • The above-question states that the while loop and do while loop can be infinite which is a true statement.
  • But it also states that the 'for' loop can not be infinite which is not a correct statement which is described above. Hence false is the correct answer to the above question.
8 0
3 years ago
Imma say something random...
Fynjy0 [20]

Answer:

Uh I don't understand what you said.

Explanation:

N/A

5 0
3 years ago
Read 2 more answers
Write c++ program to find maximum number for three variables using statement ?​
pantera1 [17]

Answer:

#include<iostream>

using namespace std;

int main(){

int n1, n2, n3;

cout<<"Enter any three numbers: ";

cin>>n1>>n2>>n3;

if(n1>=n2 && n1>=n3){

cout<<n1<<" is the maximum";}

else if(n2>=n1 && n2>=n3){

cout<<n2<<" is the maximum";}

else{

cout<<n3<<" is the maximum";}

return 0;

}

Explanation:

The program is written in C++ and to write this program, I assumed the three variables are integers. You can change from integer to double or float, if you wish.

This line declares n1, n2 and n3 as integers

int n1, n2, n3;

This line prompts user for three numbers

cout<<"Enter any three numbers: ";

This line gets user input for the three numbers

cin>>n1>>n2>>n3;

This if condition checks if n1 is the maximum and prints n1 as the maximum, if true

<em>if(n1>=n2 && n1>=n3){</em>

<em>cout<<n1<<" is the maximum";}</em>

This else if condition checks if n2 is the maximum and prints n2 as the maximum, if true

<em>else if(n2>=n1 && n2>=n3){</em>

<em>cout<<n2<<" is the maximum";}</em>

If the above conditions are false, then n3 is the maximum and this condition prints n3 as the maximum

<em>else{</em>

<em>cout<<n3<<" is the maximum";}</em>

return 0;

3 0
3 years ago
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