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3 years ago

6

If you write 0.00002836 in scientific notation, what exponent completes the notation?

1 answer:

rosijanka [135]3 years ago

6 0

2.836x10^-5 is going to be your answer

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Consider a Poisson distribution with μ = 6.

bearhunter [10]

Answer:

a) $P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

b) f(2) = 0.04462

c) f(1) = 0.01487

d) $P(X \geq 2) = 0.93803$

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of successes

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

In this question:

$\mu = 6$

a. Write the appropriate Poisson probability function.

Considering $\mu = 6$

$P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

b. Compute f (2).

This is P(X = 2). So

$P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

$P(X = 2) = \frac{e^{-6}*6^{2}}{(2)!} = 0.04462$

So f(2) = 0.04462

c. Compute f (1).

This is P(X = 1). So

$P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

$P(X = 1) = \frac{e^{-6}*6^{1}}{(1)!} = 0.01487$

So f(1) = 0.01487.

d. Compute P(x≥2)

This is:

$P(X \geq 2) = 1 - P(X < 2)$

In which:

$P(X < 2) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-6}*6^{0}}{(0)!} = 0.00248$

$P(X = 1) = \frac{e^{-6}*6^{1}}{(1)!} = 0.01487$

$P(X = 2) = \frac{e^{-6}*6^{2}}{(2)!} = 0.04462$

Then

$P(X < 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.00248 + 0.01487 + 0.04462 = 0.06197$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.06197 = 0.93803$

So

$P(X \geq 2) = 0.93803$

5 0

2 years ago

The width of a rectangle is X. Its length is 2x. How long is the diagonal of the rectangle? Express

dolphi86 [110]

Answer:

Step-by-step explanation:

7 0

2 years ago

Find y<br> y= |x−5| + |x+5| (if x>5)

velikii [3]

Answer:

$y=2x$ if $x>5$ .

Step-by-step explanation:

$|x-5|=x-5 \text{ if } x-5 \ge 0$ . This means when $x \ge 5$ .

$|x-5|=-(x-5) \text{ if } x-5 \le 0$ . This means when $x \le 5$ .

It doesn't matter where the 5 is included since either $x-5$ or $-(x-5)$ would product 0 at $x=5$ .

$|x+5|=x+5 \text{ if } x+5 \ge 0$ . This means when $x \ge -5$ .

$|x+5|=-(x+5) \text{ if } x+5 \le 0$ . This means when $x \le -5$ .

The same statement here about $x=-5$ as I about $x=5$ with the earlier expression.

So anyways we have $x>5$ .

This means $y=|x-5|+|x+5|$ can be rewritten as

$y=(x-5)+(x+5)=(x+x)+(-5+5)=2x+0=2x$ .

$y=2x$

6 0

3 years ago

After a 10% discount, the price of a T-shirt is $27. What did as the original price?

iragen [17]

Answer:

The original price was $30

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Identify the terms and like terms in the expression.

Cloud [144]

Terms of an expression are any Numbers separated by a plus or minus sign so your terms would be t, 8, & 3t

8 0

2 years ago