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NNADVOKAT [17]
3 years ago
14

Ronald spent $148.45 on school clothes. He counted his money and discovered that he had $33.55 left. How much money did he origi

nally have? Enter an equation, using m as your variable, to find how much money he originally had. Then solve the equation. An equation is . Ronald originally had $ .
Mathematics
1 answer:
FinnZ [79.3K]3 years ago
5 0

Answer:

Step-by-step explanation:

let m represent the money he originally had

m - 148.45 = 33.55

m = 33.55 + 148.45

m = 182 <==== what Ronald originally had

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Step-by-step explanation:

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2 years ago
Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the proporti
hodyreva [135]

Answer:

The sample size n = 4225

Step-by-step explanation:

We will use maximum error formula = \frac{z_{a} S.D}{\sqrt{n} }

but we will find sample size "n"

\sqrt{n}  = \frac{z_{a} S.D}{maximum error}

Squaring on both sides , we get

n  = (\frac{z_{a} S.D}{maximum error})^2

Given 99% confidence interval (z value) = 2.56

given maximum error = 0.02

n  = (\frac{z_{a} p(1-p)}{maximum error})^2

n≤ (\frac{2.56X\frac{1}{2} }{0.02}) ^{2}    ( here S.D = p(1-p) ≤ 1/2

on simplification , we get n = 4225

<u>Conclusion</u>:

The sample size of two samples is  n = 4225

<u>verification</u>:-

We will use maximum error formula = \frac{z_{a} S.D}{\sqrt{n} } = \frac{2.56 1/2}{\ \sqrt{4225} }  = 0.0196

substitute all values and simplify we get maximum error is 0.02

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3 years ago
Carmela walked 3 miles in 3/4 hour. true or false: carmela walked 1/2 mile in 30 minutes
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Answer:

1) The solve by graphing will the preferred choice when the equation is complex to be easily solved by the other means

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2x + 6y = 16

x + y = 6

We can substitute the value of x = 6 - y, into the first equation and solve from there

3) Solving an equation be Elimination, is suitable when there are two or more equations with coefficients of the form, 2·x + 6·y = 23 and x + y = 16

Multiplying the second equation by 2 and subtracting it from the first equation as follows

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2·x - 2·x + 6·y - 2·y = 23 - 32

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4) An example of a linear system that can be solved by all three methods is given as follows;

2·x + 6·y = 23

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Step-by-step explanation:

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