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NNADVOKAT [17]
4 years ago
14

Ronald spent $148.45 on school clothes. He counted his money and discovered that he had $33.55 left. How much money did he origi

nally have? Enter an equation, using m as your variable, to find how much money he originally had. Then solve the equation. An equation is . Ronald originally had $ .
Mathematics
1 answer:
FinnZ [79.3K]4 years ago
5 0

Answer:

Step-by-step explanation:

let m represent the money he originally had

m - 148.45 = 33.55

m = 33.55 + 148.45

m = 182 <==== what Ronald originally had

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Answer:

Not solutions.

Step-by-step explanation:

-5x+6y=-5

6y=-5+5x

6y=5x-5

y=5/6x-5/6

-5/6 is about -0.833

And the slope is 5/6.

So for every x there is 5/6y.

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Also 5/6*6=5. this is too low too.

So they aren't solutions.

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1 year ago
What is <br><img src="https://tex.z-dn.net/?f=8.4%20-%204.2" id="TexFormula1" title="8.4 - 4.2" alt="8.4 - 4.2" align="absmiddle
STALIN [3.7K]

Answer:

4.2

Step-by-step explanation:

\mathrm{Write\:the\:numbers\:one\:under\:the\:other,\:line\:up\:the\:decimal\:points.}

\mathrm{Add\:trailing\:zeroes\:so\:the\:numbers\:have\:the\:same\:length.}

\begin{matrix}\space\space&8&.&4\\ -&4&.&2\end{matrix}

\mathrm{Subtract\:each\:column\:of\:digits,\:starting\:from\:the\:right\:and\:working\:left}

\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:4-2=2

\frac{\begin{matrix}\space\space&8&.&\textbf{4}\\ -&4&.&\textbf{2}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\textbf{2}\end{matrix}}

\mathrm{Place\:the\:decimal\:point\:in\:the\:answer\:directly\:below\:the\:decimal\:points\:in\:the\:terms}

\frac{\begin{matrix}\space\space&8&\textbf{.}&4\\ -&4&\textbf{.}&2\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{.}&2\end{matrix}}

\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:8-4=4

\frac{\begin{matrix}\space\space&\textbf{8}&.&4\\ -&\textbf{4}&.&2\end{matrix}}{\begin{matrix}\space\space&\textbf{4}&.&2\end{matrix}}

=4.2

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