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Fudgin [204]
1 year ago
5

Complete and balance the equation for the single displacement reaction between lithium and cadmium nitrate. Phases are optional.

Chemistry
1 answer:
Mariana [72]1 year ago
5 0

Answer:

huauususuuskkajsjjja

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A solution is prepared by mixing 0.0300 mol CH2Cl2 and 0.0500 mol CH2Br2 at 25 degrees C. Assuming the solution is ideal, calcul
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Answer:

CH2Cl2 mole fraction =  0.833

CH2Br2 mole fraction = 0.167

Explanation:

Step 1: Data given

Number of moles CH2Cl2 = 0.0300 moles

Number of moles CH2Br2 = 0.0500 moles

Temperature = 25 °C

Vapor pressure of pure CH2Cl2 = 133 torr

Vapor pressure of pure CH2Br2 = 11.4 torr

Step 2:  Calculate mol fraction  in solution

Mol fraction CH2Cl2 = 0.0300 moles / (0.0300 + 0.0700)

Mol fraction CH2Cl2 = 0.300

Mol fraction CH2Br2 = 0.0700 moles / (0.0300 + 0.0700)

Mol fraction CH2Br2 = 0.700

Step 3: Calculate partial pressure

Partial pressure CH2Cl2 = 133 torr * 0.300 = 39.9 torr

Partial pressure CH2Br = 11.4 torr * 0.700 =7.98 torr

Step 4: Calculate the total pressure

total pressure = 39.9 + 7.98 = 47.88 torr

Step 5: Calculate mol fraction

partial pressure / total pressure = mole fraction

CH2Cl2 mole fraction = 39.9 / 47.88 = 0.833

CH2Br2 mole fraction = 7.98 / 47.88 = 0.167

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