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Ulleksa [173]
4 years ago
8

Which compound has the highest melting point

Chemistry
1 answer:
maks197457 [2]4 years ago
8 0
The answer is Lithium Fluoride, with a meltingpoint of 1,553°F (or 845°C).
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Calculate the number of moles in 18.5 g of aluminum thiosulfate, Al2(S2O3)3
alisha [4.7K]

Answer:

0.05 mol

Explanation:

Moles = Mass / Mr (Relative formula mass)

Ar of aluminium = 27

Ar of sulphur = 32

Ar of oxygen = 16

Mr of Al2(S2O3)2 = (27×2)+((32×2)×3)+((16×3)×3)= 390

Moles = 18.5g / 390

Moles = 0.05 mol

5 0
3 years ago
Using the periodic table, choose the more reactive nonmetal.<br> Br or As
vladimir2022 [97]
Br
First of all, As is a metalloid, not a nonmetal. Second of all, as the rows get higher on the periodic table, the elements are more reactive. As you move right on the periodic table, the elements become more reactive.
3 0
3 years ago
Separates substances based on their movement through a special paper
Rama09 [41]
This sounds like paper chromatography.  Let me know in the comments if the answer is something else.
4 0
4 years ago
How does the presence of hcl affect the charges on the complexes?
FrozenT [24]

Hydrochloric Acid (HCl) is a strong acid when it is present in the concentrated form but when it is dissolved in water (H_2O) the atoms of this compound dissociates into its respective ions as shown below:

HCl(aq.) + H_2O(aq.) \rightarrow H_3O^+(aq.) + Cl^-(aq.)

When we add HCl to any complex in its concentrated form the complex does not react at all but when its diluted to 6M and is kept for many hours, the complex reacts slowly. For eg:

[Co(NH_3)_6]^3^+(aq.) + HCl(aq.) \rightarrow  [Co(NH_3)_5Cl]^2^+(aq.) + NH_4^+ (aq.)

As seen from the above reaction it can be seen the positive charge on the complex is reduced by 1 unit because one Cl^- ion gets attached to the centre metal atom, therefore we can conclude that the charge on complex gets reduced by 1 unit when HCl reacts with the complex.

7 0
3 years ago
An air/gasoline vapor mix in an automobile cylinder has an initial temperature of 180 ∘C and a volume of 13 cm3 . If the mixture
earnstyle [38]

Answer:

The final volume will be 24.7 cm³

Explanation:

<u>Step 1:</u> Data given:

Initial temperature = 180 °C

initial volume = 13 cm³ = 13 mL

The mixture is heated to a fina,l temperature of 587 °C

Pressure and amount = constant

<u>Step 2: </u>Calculate final volume

V1/T1 = V2/T2

with V1 = the initial volume V1 = 13 mL = 13*10^-3

with T1 = the initial temperature = 180 °C = 453 Kelvin

with V2 = the final volume = TO BE DETERMINED

with T2 = the final temperature = 587 °C = 860 Kelvin

V2 = (V1*T2)/T1

V2 = (13 mL *860 Kelvin) /453 Kelvin

V2 = 24.68 mL = 24.7 cm³

The final volume will be 24.7 cm³

5 0
3 years ago
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