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vova2212 [387]
3 years ago
5

Which of the following groups of materials would

Chemistry
2 answers:
qwelly [4]3 years ago
8 0

Answer:

C

Explanation:

Nikitich [7]3 years ago
4 0
The wrong answers for sure are B and D, I assume the answer is C
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How many grams of chlorine gas can be produced when 50.0 grams of aluminum chloride decompose? 2AlCl3→ 2Al + 3Cl2
lianna [129]

Answer:

Explanation:

Approx.

425

⋅

g

Explanation:

2

A

l

(

s

)

+

3

C

l

2

(

g

)

→

2

A

l

C

l

3

(

s

)

You have given a stoichiometrically balanced equation, so bravo.

The equation explicitly tells us that

54

⋅

g

of aluminum metal reacts with

6

×

35.45

⋅

g

C

l

2

gas to give

266.7

⋅

g

of

aluminum trichloride

hope this helps

6 0
2 years ago
3. Determine the moles of sodium, Na, containing 7.9x1024 atoms.​
-BARSIC- [3]

Answer:

12.7mol Na.

Explanation:

Hello there!

In this case, according to the concept of mole, which stands for the amount of substance, we can recall the concept of Avogadro's number whereby we understand that one mole of any substance contains 6.022x10²³ particles, for the given atoms of sodium, we can calculate the moles as shown below:

7.9x10^{23}atoms*\frac{1mol}{6.022x10^{23}atoms} \\\\

Thus, by performing the division we obtain:

12.7molNa

Regards!

8 0
3 years ago
What kind of product is formed when a ketone reacts with a grignard reagent followed by protonation?
svet-max [94.6K]

c. a tertiary alcohol; when a ketone reacts with a grignard reagent followed by protonation a tertiary alcohol is formed.

More about tertiary alcohol:

No hydrogen atoms are bonded to the functional group's carbon in a tertiary alcohol. Alcohols that have a hydroxyl group bonded to the carbon atom and are linked to three alkyl groups are referred to as tertiary alcohols. These alcohols' structural makeup largely determines their physical characteristics.

This -OH group's existence enables alcohols to create hydrogen bonds with the atoms next to them. Because of this weak connection, alcohols have higher boiling points than their alkane counterparts.

The alcohol is referred to as a tertiary (3°) alcohol if the carbon atom carrying the alcohol group is connected to three other carbon atoms in the alcohol molecule.

Learn more about tertiary alcohol here:

brainly.com/question/17419424

#SPJ4

8 0
2 years ago
Gaseous methane (CH4) reacts with gaseous oxygen gas (02) to produce gaseous carbon dioxide (CO2) and gaseous water (H20). What
Mariana [72]

Answer:

Theoretical yield = 3.51 g

Explanation:

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

For CH_4  :-

Mass of CH_4  = 1.28 g

Molar mass of CH_4  = 16.04 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{1.28\ g}{16.04\ g/mol}

Moles_{CH_4}= 0.0798\ mol

For O_2  :-

Mass of O_2  = 10.1 g

Molar mass of O_2  = 31.998 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{10.1\ g}{31.998\ g/mol}

Moles_{O_2}= 0.3156\ mol

According to the given reaction:

CH_4+2O_2\rightarrow CO_2+2H_2O

1 mole of methane gas reacts with 2 moles of oxygen gas

0.0798 mole of methane gas reacts with 2*0.0798 moles of oxygen gas

Moles of oxygen gas = 0.1596 moles

Available moles of oxygen gas = 0.3156 moles

<u>Limiting reagent is the one which is present in small amount. Thus, CH_4 is limiting reagent. </u>

The formation of the product is governed by the limiting reagent. So,

1 mole of methane gas on reaction produces 1 mole of carbon dioxide.

0.0798 mole of methane gas on reaction produces 0.0798 mole of carbon dioxide.

Mole of carbon dioxide = 0.0798 mole

Molar mass of carbon dioxide = 44.01 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

0.0798\ moles= \frac{Mass}{44.01\ g/mol}

Mass of CO_2 = 3.51 g

<u> Theoretical yield = 3.51 g</u>

3 0
3 years ago
Help!!! chemistry electrolysis
Tpy6a [65]
Electrolysis can be used to separate a substance into its original components/elements and it was through this process that a number of elements have been discovered and are still produced in today's industry.
5 0
3 years ago
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