Answer:
33.8 m
Explanation:
(a) We want to know the molality of nitric acid in a concentrated solution of nitric acid (68.0% HNO₃ by mass).
Step 1: Determine the mass of HNO₃ and water in 100 grams of solution.
Step 2: Convert the mass of HNO₃ to moles.
Step 3: Convert the mass of water to kilograms.
Step 4: Calculate the molality.
(b)
Step 1
In 100 g of solution, there are 68.0 g of HNO₃ and 100 g - 68.0 g = 32.0 g of water.
Step 2
The molar mass of HNO₃ is 63.01 g/mol. The moles corresponding to 68.0 g are:
68.0 g × (1 mol/63.01 g) = 1.08 mol
Step 3
The mass of water is 32.0 g = 0.0320 kg
Step 4
The molality of HNO₃ is:
m = moles of solute / kilograms of solvent
m = 1.08 mol / 0.0320 kg
m = 33.8 m
Answer:
A car traveling 25 KM/H
Explanation:
It has the largest mass and speed.
The question above can be answered by using the volume balance concept. Two equations can be established by total volume balance and the component (acid) volume balance.
If we let x be the volume of the 12% acid solution, the volume of the 20% acid solution will have to be 100 - x.
x + (100 - x) = 100
Then, the acid mass balance will give us the equation,
(x)(0.12) + (100 - x)(0.20) = (100)(0.18)
Simplifying,
0.12x + 20 - 0.20x = 18
-0.08x = 20 - 18
-0.08x = 2
The value of x from the equation is 25.
<em>Hence, the volume of the 12% acid solution is 20 galloons and that of the 20% acid solution is 75 galloons. </em>
Answer:
D
Explanation:
according to boyle's law the temperature and pressure of a gas are inversely proportional given by the equation
p1v1=p2v2
In this case p1 is 9.5,v1 is 1.7,v2 is 1.1 and we have to find p2
9.5×1.7=p2×1.1
16.15/11=1.1p2/1.2
p2=14.7
I hope this helps
The correct option is A.
Option A is the correct answer because the question asked in that option can easily be verified by using scientific method. The question is considered to be science based because scientific methods can be used to answer the question. To determine the density of water, all that one has to do is to find the mass and the volume of a sample of water and then divide the ratio.
